Snowflake ARA-C01 Exam - Topic 6 Question 46 Discussion

Actual exam question for Snowflake's ARA-C01 exam

Question #: 46
Topic #: 6

Two queries are run on the customer_address table:

create or replace TABLE CUSTOMER_ADDRESS ( CA_ADDRESS_SK NUMBER(38,0), CA_ADDRESS_ID VARCHAR(16), CA_STREET_NUMBER VARCHAR(IO) CA_STREET_NAME VARCHAR(60), CA_STREET_TYPE VARCHAR(15), CA_SUITE_NUMBER VARCHAR(10), CA_CITY VARCHAR(60), CA_COUNTY

VARCHAR(30), CA_STATE VARCHAR(2), CA_ZIP VARCHAR(10), CA_COUNTRY VARCHAR(20), CA_GMT_OFFSET NUMBER(5,2), CA_LOCATION_TYPE

VARCHAR(20) );

ALTER TABLE DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS ADD SEARCH OPTIMIZATION ON SUBSTRING(CA_ADDRESS_ID);

Which queries will benefit from the use of the search optimization service? (Select TWO).

Aselect * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where substring(CA_ADDRESS_ID,1,8)= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,8);

Bselect * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,16);

Cselect * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID LIKE '%BAAASKD%';

Dselect * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID LIKE '%PHPP%';

Eselect * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID NOT LIKE '%AAAAAAAAPHPPL%';

Show Suggested Answer

Suggested Answer: A, B

The use of the search optimization service in Snowflake is particularly effective when queries involve operations that match exact substrings or start from the beginning of a string. The ALTER TABLE command adding search optimization specifically for substrings on the CA_ADDRESS_ID field allows the service to create an optimized search path for queries using substring matches.

Option A benefits because it directly matches a substring from the start of the CA_ADDRESS_ID, aligning with the optimization's capability to quickly locate records based on the beginning segments of strings.

Option B also benefits, despite performing a full equality check, because it essentially compares the full length of CA_ADDRESS_ID to a substring, which can leverage the substring index for efficient retrieval. Options C, D, and E involve patterns that do not start from the beginning of the string or use negations, which are not optimized by the search optimization service configured for starting substring matches. Reference: Snowflake's documentation on the use of search optimization for substring matching in SQL queries.

by Regenia at Feb 12, 2025, 07:16 PM

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Krystal

3 months ago

Totally agree with A, it's all about that substring match!

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Rosina

3 months ago

Wait, are we sure about A? Seems a bit off to me.

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Edison

3 months ago

C and D seem like they won't get any help from that optimization.

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Kimbery

4 months ago

I think B is a better choice, though.

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Stacey

4 months ago

Query A will definitely benefit from the optimization!

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Natalie

4 months ago

I think option A and B are the ones that will benefit, but I’m not confident about the specifics of how search optimization works with LIKE clauses.

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Ligia

4 months ago

I feel like option A could be a good candidate since it uses substring, but I'm confused about option B. Does it really benefit from optimization?

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Glenn

4 months ago

I remember practicing a similar question where LIKE queries didn't benefit from optimization, so I think options C and D might not be the right choice here.

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Corinne

5 months ago

I think the queries that use substring with a specific length might benefit from search optimization, but I'm not entirely sure which ones.

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Erick

5 months ago

This is a good opportunity to apply what I've learned about search optimization and how it can improve query performance. I think I've got a handle on it, so I'll go ahead and select the two queries that I believe will benefit.

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Sunshine

5 months ago

I'm a bit confused by the different ways the queries are using the CA_ADDRESS_ID column. I'll need to double-check the details to make sure I understand which ones will actually use the search optimization.

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Dorothy

5 months ago

Okay, let me think this through. Queries A and B both use SUBSTRING on the CA_ADDRESS_ID, so those should be the ones that benefit. I'll select those two.

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Shaniqua

5 months ago

Hmm, the search optimization is on the SUBSTRING of the CA_ADDRESS_ID column, so I'm guessing the queries that use SUBSTRING or LIKE on that column will be the ones that benefit.

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Markus

5 months ago

This looks like a tricky one. I'll need to carefully read through the question and the SQL queries to understand which ones will benefit from the search optimization service.

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Yasuko

12 months ago

Wait, did they really name the table 'CUSTOMER_ADDRESS'? I guess they wanted to make it as descriptive as possible.

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Nu

12 months ago

Hmm, I wonder if the search optimization service can help me find my lost car keys as well? Just kidding, but this seems pretty useful for querying address data.

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Twanna

12 months ago

I'm not sure about D and E, but C looks like it could also benefit from the search optimization service.

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Veronika

11 months ago

User: I'm not sure about D and E, but C looks like it could also benefit from the search optimization service.

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Xuan

11 months ago

C) select * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID LIKE '%BAAASKD%';

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Carole

11 months ago

B) select * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,16);

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Aimee

11 months ago

A) select * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where substring(CA_ADDRESS_ID,1,8)= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,8);

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Kenneth

1 year ago

I believe queries C, D, and E will benefit as well because they are using LIKE operators on CA_ADDRESS_ID.

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Felicidad

1 year ago

I agree with Trina. Queries A and B are using substring functions on CA_ADDRESS_ID.

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Trina

1 year ago

I think queries A and B will benefit from the search optimization service.

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Eileen

1 year ago

The search optimization service will definitely benefit queries A and B, since they're using the substring function on the CA_ADDRESS_ID column.

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Carissa

1 year ago

B) select * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where CA_ADDRESS_ID= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,16);

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Carissa

1 year ago

A) select * from DEMO_DB.DEMO_SCH.CUSTOMER_ADDRESS Where substring(CA_ADDRESS_ID,1,8)= substring('AAAAAAAAPHPPLBAAASKDJHASLKDJHASKJD',1,8);

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