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Pegasystems PEGACPLSA88V1 Exam - Topic 6 Question 4 Discussion

Actual exam question for Pegasystems's PEGACPLSA88V1 exam
Question #: 4
Topic #: 6
[All PEGACPLSA88V1 Questions]

Users are spending excess time researching duplicate cases to determine whether to process or resolve the cases.

Which two options allow you to reduce the number of potential duplicate cases? (Choose two.)

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Suggested Answer: A, D

by Leota at Mar 10, 2024, 06:46 PM

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Lucina
3 months ago
I heard increasing weights can actually complicate things.
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Broderick
3 months ago
Wait, are we sure about that? Sounds risky!
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Dana
3 months ago
Decreasing the weights? Not sure that’s a good idea.
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Alverta
4 months ago
Totally agree, that should help filter out duplicates!
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Wynell
4 months ago
I think increasing the weighted condition sum threshold makes sense.
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Ty
4 months ago
I feel like decreasing the weighted condition sum threshold is definitely a good choice, but I can't recall if the other option is right.
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Marti
4 months ago
I'm a bit confused about the weights. Wouldn't increasing them lead to more duplicates?
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Valene
4 months ago
I remember practicing a similar question, and I think increasing the weighted condition sum threshold could reduce duplicates too.
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Stefanie
5 months ago
I think decreasing the weights of the weighted conditions might help, but I'm not entirely sure about the second option.
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Ahmad
5 months ago
Hmm, I'm leaning towards option C - increasing the weighted condition sum threshold. That seems like it would be the most straightforward way to reduce the number of potential duplicates.
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Bobbye
5 months ago
I'm a bit confused on the difference between increasing and decreasing the weights and the threshold. I'll need to review those concepts again before deciding.
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Harrison
5 months ago
I think increasing the weighted condition sum threshold might be the way to go. That would make it harder for cases to be flagged as potential duplicates.
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Eveline
5 months ago
Okay, let's see. Decreasing the weights of the weighted conditions sounds like it could reduce the number of potential duplicates, but I'm not sure if that's the best option.
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Elenore
5 months ago
Hmm, this seems like a tricky one. I'll need to think through the options carefully to determine the best approach.
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Amira
5 months ago
No problem, I've got this. Sensitivity is the ratio of true positives to the sum of true positives and false negatives. I can use the values in the matrix to calculate that directly.
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Whitney
5 months ago
I'm leaning towards TCP/IP, but I can't shake the feeling that there's something specific about HTTP servers that relates to controlling cameras.
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Aleisha
5 months ago
Ah, I think I've got it! "Modified American Plan" must be referring to a hotel package that includes some meals, but not a full board. So the answer is probably A, half-board. I feel good about that one.
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Jade
2 years ago
I think increasing the threshold could actually lead to more potential duplicate cases.
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Torie
2 years ago
But wouldn't increasing the weighted condition sum threshold be a better option?
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Sarina
2 years ago
I agree with Reuben, decreasing the weights could help reduce potential duplicate cases.
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Reuben
2 years ago
I think we should decrease the weights of the weighted conditions.
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