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Pegasystems PEGACPLSA88V1 Exam - Topic 1 Question 16 Discussion

Actual exam question for Pegasystems's PEGACPLSA88V1 exam
Question #: 16
Topic #: 1
[All PEGACPLSA88V1 Questions]

A queue processor is configured with the value of the Max attempts field is 4, the value of the Initial delay field is 2 minutes and the the value of the Delay factor field is 2 for processing retries.

What is the delay between the second and third attempt, assuming each previous attempt fails?

Show Suggested Answer Hide Answer
Suggested Answer: A, B

Max Attempts: The maximum number of retry attempts set is 4.

Initial Delay: The initial delay before the first retry attempt is 2 minutes.

Delay Factor: The delay factor is set to 2, which means the delay doubles with each retry.

Calculating Delays:

First attempt fails, delay before second attempt = Initial delay = 2 minutes.

Second attempt fails, delay before third attempt = Initial delay * Delay factor = 2 minutes * 2 = 4 minutes.

Third attempt fails, delay before fourth attempt = 4 minutes * Delay factor = 4 minutes * 2 = 8 minutes.

Delay Between Attempts: The question specifically asks for the delay between the second and third attempt, which is calculated as 8 minutes.


Pega documentation on queue processor configuration.

Pega Platform 8.x help files related to processing retries and delay factors.

Contribute your Thoughts:

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Alease
3 months ago
8 minutes makes sense based on the factors given.
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Adolph
3 months ago
Wait, are we sure about that? Sounds off.
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Shizue
3 months ago
I thought it would just be 4 minutes.
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Kimberlie
4 months ago
Definitely, so it should be 8 minutes.
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Dalene
4 months ago
The delay doubles each time, right?
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Murray
4 months ago
I’m a bit confused about the total delay. Is it just the delay for the third attempt, or do we add the previous delays together? I need to think this through.
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Jettie
4 months ago
I practiced a similar question, and I think the delays are cumulative. So, if the first delay is 2 minutes, the second should be 4 minutes, but I can't recall the exact timing for the third.
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Chana
4 months ago
I remember something about exponential backoff in retries. If the initial delay is 2 minutes and the factor is 2, wouldn't the second delay be 4 minutes?
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Lura
5 months ago
I think the delay between attempts increases based on the Delay factor, but I'm not entirely sure how to calculate it for the second and third attempts.
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Lettie
5 months ago
This is tricky, I'm not totally confident I understand how the delay factor works in this context. I'll need to review the information provided again.
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Zack
5 months ago
I've got a good strategy for this - I'll start by calculating the delay for the first and second attempts, then use that to find the delay for the third attempt.
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Winifred
5 months ago
Okay, let me break this down - the initial delay is 2 minutes, and the delay factor is 2. So I just need to calculate the delay for each attempt.
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Willie
5 months ago
This question seems straightforward, I think I can work through it step-by-step.
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Lauran
5 months ago
Hmm, I'm a bit unsure about how the delay factor is applied here. I'll need to think it through carefully.
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Aileen
5 months ago
I'm a bit confused by this one. The asterisk is throwing me off, and I'm not sure how it relates to the different types of nodes or list structures mentioned in the options. I'll need to re-read the question and options carefully.
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Samira
5 months ago
Hmm, I'm a bit confused on this one. I'll need to review the PAN-OS documentation on External Dynamic Lists and how they integrate with MineMeld.
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Willodean
2 years ago
Haha, this is a tricky one. I bet the answer is 8 minutes, just to really mess with us. You know, some exam questions are designed to be sneaky like that.
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Jerry
2 years ago
Wait, I think I got this. The delay between the second and third attempt should be 8 minutes, since the delay doubles with each attempt. The Delay factor of 2 means the delay is multiplied by 2 each time.
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Dino
2 years ago
Ah, I see. The delay is calculated by multiplying the Initial delay (2 minutes) by the Delay factor (2) for each subsequent attempt. So the delay between the second and third attempt is 2 x 2 = 4 minutes.
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Gladys
2 years ago
D) 6 minutes
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Avery
2 years ago
C) 2 minutes
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Christene
2 years ago
B) 4 minutes
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Kenneth
2 years ago
A) 8 minutes
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Harrison
2 years ago
But the Initial delay is 2 minutes, so it should be 6 minutes in total.
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Louann
2 years ago
I think it's 8 minutes because of the Delay factor of 2.
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Edwin
2 years ago
Hmm, let's see. If the Initial delay is 2 minutes and the Delay factor is 2, the delay between the second and third attempt should be 4 minutes. I'm pretty sure option B is the correct answer.
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Jamal
2 years ago
Looks like we all agree on the answer. Option B) 4 minutes for the delay between the second and third attempt.
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Lucina
2 years ago
Great, thanks for confirming. Option B) 4 minutes it is.
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Emogene
2 years ago
Yes, that makes sense. So the correct answer is option B) 4 minutes.
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Pearlie
2 years ago
I think you're right, the delay between the second and third attempt should be 4 minutes.
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Harrison
2 years ago
The delay between the second and third attempt is 4 minutes.
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