Nokia 4A0-100 Exam - Topic 1 Question 119 Discussion

Actual exam question for Nokia's 4A0-100 exam

Question #: 119
Topic #: 1

[All 4A0-100 Questions]

How many subnets and host addresses are obtained by subnetting network 201.148.26.0/24 using a /26 subnet mask?

A4 subnets, 64 hosts per subnet

B8 subnets, 32 hosts per subnet

C4 subnets, 62 hosts per subnet

D8 subnets, 30 hosts per subnet

Show Suggested Answer

Suggested Answer: C

Nokia IP Fundamentals Guide -- Chapter: ''Subnetting and Address Calculations''

Subnet Math -- RFC 950 principles

by Francene at Nov 24, 2025, 04:02 AM

Limited Time Offer

25%

Off

Get Premium 4A0-100 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Marge

1 hour ago

I remember /26 gives us 4 bits for subnets. So, B is correct!

upvoted 0 times

...

Sean

5 days ago

D seems right. 8 subnets, 30 hosts.

upvoted 0 times

...

Darci

10 days ago

I lean towards C. 4 subnets, 62 hosts.

upvoted 0 times

...

Iraida

16 days ago

I feel like it's A. 4 subnets, 64 hosts.

upvoted 0 times

...

Tyra

21 days ago

Wait, how can there be 30 hosts? That seems weird!

upvoted 0 times

...

King

26 days ago

I'm not sure about that, but D) 8 subnets, 30 hosts sounds off.

upvoted 0 times

...

Cruz

1 month ago

No way, it's C) 4 subnets, 62 hosts!

upvoted 0 times

...

Leslie

1 month ago

I think it's A) 4 subnets, 64 hosts.

upvoted 0 times

...

Clare

2 months ago

Definitely B) 8 subnets, 32 hosts per subnet.

upvoted 0 times

...

Kenneth

2 months ago

Subnetting? More like sub-netting my brain. I need a subnet-tle approach to these questions.

upvoted 0 times

...

Audry

2 months ago

I thought the answer was "a partridge in a pear tree." Clearly, I'm in the wrong exam.

upvoted 0 times

...

Nohemi

2 months ago

D) 8 subnets, 30 hosts per subnet. Wait, is that right? I always get these subnet questions mixed up. Maybe I need to review my notes again.

upvoted 0 times

...

Carmen

3 months ago

B) 8 subnets, 32 hosts per subnet. I'm pretty sure that's the right answer, but I could be wrong. Subnetting is tricky sometimes.

upvoted 0 times

...

Twana

3 months ago

C) 4 subnets, 62 hosts per subnet. That's the correct answer, as subnetting 201.148.26.0/24 with a /26 mask gives you 4 subnets with 62 usable hosts each.

upvoted 0 times

...

Corrie

3 months ago

I’m pretty confident that subnetting a /24 to /26 gives us 4 subnets, but I can't recall the exact number of usable hosts right now.

upvoted 0 times

...

Lashawn

3 months ago

I think we get 4 subnets with 62 usable hosts each, but I might be mixing it up with a different question we practiced.

upvoted 0 times

...

Lorita

3 months ago

I remember that when we subnet a /24 to a /26, we double the number of subnets, but I'm not sure how many hosts that gives us.

upvoted 0 times

...

Dona

3 months ago

Ah, subnetting questions - my nemesis! But I'll give it my best shot. Gotta remember those subnet mask calculations...

upvoted 0 times

...

Floyd

4 months ago

Subnetting is one of my stronger areas, so I'm feeling pretty confident about this. I'll quickly calculate the subnet and host details to determine the right answer.

upvoted 0 times

...

Samuel

4 months ago

I'm a bit confused on how to approach this. Subnetting can get tricky, but I'll try to work through it step-by-step and see if I can figure it out.

upvoted 0 times

...

Evette

4 months ago

I think it's B. 8 subnets, 32 hosts each.

upvoted 0 times

...

Mozelle

5 months ago

A) 4 subnets, 64 hosts per subnet. Hmm, I thought that was the right answer, but now I'm second-guessing myself. Subnet math is not my strong suit.

upvoted 0 times

...

Gary

5 months ago

I feel like we did a similar problem where we had to calculate subnets and hosts, and I think it was 8 subnets with 30 hosts.

upvoted 0 times

...

Allene

5 months ago

Okay, let's see. The network is 201.148.26.0/24, and we need to subnet using a /26 mask. I think that means we'll have 4 subnets with 62 hosts each, so I'll go with option C.

upvoted 0 times

...