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C++ Institute CPP Exam - Topic 4 Question 70 Discussion

What happens when you attempt to compile and run the following code?#include #include #include using namespace std;templatestruct Out {ostream & out;Out(ostream & o): out(o){}void operator() (const T & val ) { out
E) 1 2 3 4
A) 8 10 5 1 4 6 2 7 9 3
B) 4 5 6 7 8 9 10
C) 1 2 3 4 5 6 7 8 9 10
D) compilation error

C++ Institute CPP Exam - Topic 4 Question 70 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 70
Topic #: 4
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

deque d1(t, t+10);

deque::iterator it = lower_bound(d1.begin(), d1.end(), 4);

for_each(it, d1.end(), Out(cout));cout<

return 0;

}

Program outputs:

Show Suggested Answer Hide Answer
Suggested Answer: E

by Daniela at Aug 05, 2023, 08:53 AM

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Casie
9 months ago
I thought it would print all the numbers in order, but I guess not!
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Vanesa
10 months ago
It's definitely not a compilation error.
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Corinne
10 months ago
Wait, are you sure? I thought it would be something else.
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Dominque
10 months ago
Totally agree, that's what I got too!
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Stefan
10 months ago
The program outputs 4 5 6 7 8 9 10.
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Mitsue
10 months ago
I have a feeling there might be a compilation error, but I can't pinpoint why. I should have paid more attention to the iterator usage.
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Allene
11 months ago
I practiced a similar question, and I feel like the output could be the elements starting from 4, but I can't recall if it includes 4 itself.
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Deane
11 months ago
I remember something about `lower_bound` returning an iterator to the first element not less than the given value, so it might start from 4.
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Ceola
11 months ago
I think the code should compile fine since all the includes seem correct, but I'm not sure what the output will be.
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Carlee
11 months ago
Based on the information provided, I think option B about emails consuming Super Messages is the most likely explanation. I'll make sure to double-check the details around that in my preparation.
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Marshall
11 months ago
Okay, I remember discussing this in class. The capitalization rate should be a blend of the debt and equity components, so I'll select option C.
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Pearline
11 months ago
This seems like a straightforward vocabulary question. I'll carefully read through the options and choose the one that best fits the context.
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Maryanne
1 year ago
The code looks pretty straightforward, but I can't help but wonder if the programmer had a bad day when they wrote this. Anyway, I'm going with A.
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Lashunda
1 year ago
Wait, is the lower_bound function supposed to return the element itself or the first element greater than the value? I'm not sure about the answer.
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Carmelina
1 year ago
Exactly, that's why the answer is B.
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Carmelina
1 year ago
So the output will start from 4.
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Carmelina
1 year ago
It returns the first element greater than or equal to the value.
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Carmelina
1 year ago
B) 2 3 4 5 6 7 8 9 10 11
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Chuck
1 year ago
Haha, looks like we're sorting a deque in reverse order. The correct answer is C.
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Raymon
1 year ago
Definitely C, it's sorting in descending order.
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Raymon
1 year ago
Yeah, it's sorting in reverse. C is the right answer.
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Raymon
1 year ago
I agree, the correct answer is C.
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Ty
1 year ago
I think the code will compile without any errors, so the answer is not E.
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Alecia
1 year ago
The output should be 4 5 6 7 8 9 10, so the correct answer is A.
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Maddie
1 year ago
Great job! You understood the code correctly.
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Maddie
1 year ago
That's correct! The output is indeed 4 5 6 7 8 9 10.
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Patria
1 year ago
That's correct! The output should be 4 5 6 7 8 9 10.
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Maddie
1 year ago
A) 1 2 3 4 5 6 7 8 9 10
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Patria
1 year ago
A) 1 2 3 4 5 6 7 8 9 10
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Shalon
1 year ago
I'm not sure, but I think the answer is A) 1 2 3 4 5 6 7 8 9 10 because lower_bound returns an iterator to the first element that is not less than the value passed, which is 4 in this case.
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Lewis
1 year ago
I agree with Viola, the lower_bound function returns an iterator to the first element that is not less than the value passed, so the output should be A) 1 2 3 4 5 6 7 8 9 10.
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Viola
1 year ago
I think the answer is A) 1 2 3 4 5 6 7 8 9 10 because lower_bound finds the first element that is not less than 4 in the deque.
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