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The formula for reliability during constant failure rate conditions is:
Use this formula to find the reliability of a product at 800 hours if MTBF = 600 hours.
Suggested Answer: D
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38 comments · newest first
SU
Suzan
10 months ago
I thought it would be higher, honestly.
GO
Goldie
11 months ago
Totally agree, 0.37 makes sense for 800 hours.
VE
Veronika
11 months ago
Wait, are you sure about that? Seems low.
JO
Joni
11 months ago
I calculated it too, and I got 0.37!
AB
Abel
11 months ago
The formula is R(t) = e^(-t/MTBF).
MA
Mabel
12 months ago
I vaguely remember that the reliability decreases as time increases, so maybe the answer is one of the lower options like 0.26 or 0.37.
HE
Heidy
12 months ago
I feel like I should be able to calculate this, but I’m confused about the exponent part. Does it really just involve plugging in the numbers?
CA
Caitlin
12 months ago
I think I practiced a similar question, and I got a number around 0.37, but I can't recall if that was for 600 hours or something else.
ME
Merrilee
1 year ago
I remember the reliability formula is R(t) = e^(-t/MTBF), but I'm not sure how to apply it for 800 hours.
FE
Felicia
1 year ago
Okay, I've got it. The reliability formula is R(t) = e^(-t/MTBF), where t is the time and MTBF is the mean time between failures. Plugging in the values, I get 0.87. Looks like A is the correct answer.
AR
Arletta
1 year ago
This looks straightforward. I'll just plug in the values and see which answer choice matches my calculation. The MTBF is 600 hours, and the time is 800 hours, so the reliability should be around 0.78.
JE
Jerrod
1 year ago
Hmm, I'm a little unsure about this one. I remember the formula, but I'm not sure if I'm supposed to use the given time or the MTBF in the exponent. Let me think this through step-by-step.
MI
Micheal
1 year ago
Okay, I think I've got this. The formula for reliability under constant failure rate conditions is R(t) = e^(-t/MTBF). So I just need to plug in the values and calculate.
AH
Ahmad
1 year ago
Wait, I'm confused. Is the reliability the same as the probability of failure? I thought they were different concepts. I better review my notes on reliability calculations before attempting this.
DI
Diane
1 year ago
I feel pretty confident about this one. I've covered this material in my studies, so I should be able to identify the three correct answers without too much trouble.
JE
Jerry
1 year ago
I'm a little unsure about how to best extract the SSID from the return_val data. I'll need to spend some time carefully analyzing the structure to make sure I'm pulling the right information. But I think I can figure this out.
UL
Ula
1 year ago
I'm not entirely sure about the shadow price concept. I think it relates to the contribution from an extra unit of a scarce resource, but I'm a bit hazy on the details.
CH
Christiane
1 year ago
Ha! I bet the answer is D. 0.26. Just kidding, I know it's A. Gotta keep a sense of humor, right? Now, where's the coffee...
ST
Stephen
1 year ago
Actually, I believe it's C) 0.37.
PE
Pete
1 year ago
No way, it's definitely B) 0.78.
ZA
Zachary
1 year ago
I think the answer is A) 0.87.
GE
Gerald
1 year ago
Alright, time to put on my thinking cap. Okay, got it! The formula is R = e^(-t/MTBF), and with the given values, it comes out to 0.87. Nice and simple, just the way I like it.
LO
Louisa
1 year ago
User 4: I think it's E) none of the above, let's double-check the formula.
SA
Sabina
1 year ago
User 3: I agree with Paul, A) 0.87 seems correct.
PA
Paul
1 year ago
User 2: Are you sure about that? I think it might be B) 0.78
NG
Ngoc
1 year ago
User 1: The answer is A) 0.87
CA
Carman
1 year ago
Wait, what? How did you guys get 0.87? I calculated it as 0.78. *scratches head* Maybe I'm missing something here...
HE
Heike
2 years ago
Hmm, I'm not sure about this one. Let me double-check the formula... Yep, A is the right choice. Nailed it!
ED
Edmond
1 year ago
Hmm, I'm not sure about this one. Let me double-check the formula... Yep, A is the right choice. Nailed it!
JI
Jimmie
1 year ago
Great job! A is the correct answer.
FA
Fabiola
1 year ago
I'm pretty confident it's A) 0.87
FR
Freeman
1 year ago
I think it's A) 0.87
LY
Lynda
1 year ago
Are you sure? I'm leaning towards B) 0.78
JU
Julieta
1 year ago
I think it's A) 0.87
CO
Coral
2 years ago
Alright, let's see... R = e^(-t/MTBF), so plugging in the values, we get R = e^(-800/600) = 0.87. Looks like A is the correct answer!
ST
Stevie
2 years ago
I'm not sure, but I think the formula involves MTBF and failure rate.
KA
Karl
2 years ago
I disagree, I believe the answer is B) 0.78.
AL
Alex
2 years ago
I think the answer is A) 0.87.