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ASQ CSSBB Exam - Topic 10 Question 97 Discussion

Posted by Dan on Sep 18, 2024 at 07:38 AM

An x-bar and R chart has four part measurements per sample The control limits on the averages chart are 2.996 and 3.256. Assume the process data form a normal distribution.What is the probability that the next part measurement falls outside the control limits?

Suggested Answer: C

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32 comments · newest first
RU
Ruby 10 months ago
Yeah, I agree with A, seems right to me!
WI
Wilda 11 months ago
Wait, are we sure about the normal distribution assumption?
DI
Dianne 11 months ago
Definitely not E, that seems way too high.
RO
Royce 11 months ago
I think the probability is pretty low, maybe A?
RO
Rozella 11 months ago
The control limits are 2.996 and 3.256.
FR
Frederick 12 months ago
I feel like the answer might be around 0.0027, but I’m not confident. I should have practiced more with these types of problems.
EV
Evette 12 months ago
If the process is normally distributed, I believe the area outside the control limits is what we need to find, but I can't recall the exact method.
KR
Kristeen 12 months ago
I remember a similar question where we had to find the probability of falling outside control limits, and I think it involved using the normal distribution table.
MA
Marya 1 year ago
I think we need to calculate the z-scores for the control limits, but I'm not entirely sure how to do that with the averages.
CR
Cristina 1 year ago
Alright, let's think this through step-by-step. I need to find the z-score corresponding to the control limits, then use a normal distribution table to get the probability. I've got a good strategy here.
TR
Troy 1 year ago
Wait, is this a one-tailed or two-tailed probability? I better double-check the question to make sure I'm interpreting it correctly. Don't want to mess this up.
LA
Layla 1 year ago
This seems straightforward enough. I just need to plug the given control limits into the standard normal distribution formula and calculate the probability. I've got this!
KA
Kate 1 year ago
Hmm, I'm a bit confused about the normal distribution assumption here. Do I need to standardize the data before calculating the probability? I'll have to review that part.
KA
Kanisha 1 year ago
Okay, this looks like a probability question involving an x-bar and R chart. I'll need to remember the formulas for calculating the control limits and the probability of a part measurement falling outside those limits.
RE
Reuben 1 year ago
I've got this! Based on the weight of 9kg and price of 10, the expected result is C - no need to pay in cash, free delivery. The decision tables clearly show that for items under 10kg and under 20, free delivery is provided.
HU
Hubert 1 year ago
Alright, time to put on my best poker face and make an educated guess. Here goes nothing!
TA
Tamie 1 year ago
↳ replying to Hubert
D) 0.1362
NO
Noelia 1 year ago
↳ replying to Hubert
C) 0.0681
YU
Yuriko 1 year ago
↳ replying to Hubert
B) 0.0027
LE
Leatha 1 year ago
↳ replying to Hubert
A) 0.00135
ED
Edwin 1 year ago
I'm feeling a little like a mad scientist trying to solve this problem. Where's my lab coat when I need it?
DA
Dalene 1 year ago
↳ replying to Edwin
C) 0.0681
JO
Josephine 1 year ago
↳ replying to Edwin
B) 0.0027
LA
Laila 1 year ago
↳ replying to Edwin
A) 0.00135
NI
Nicolette 1 year ago
Oooh, I think I know this one! Let me work it out step-by-step.
ST
Stefan 1 year ago
↳ replying to Nicolette
C) 0.0681
MA
Madalyn 1 year ago
↳ replying to Nicolette
B) 0.0027
EL
Elin 1 year ago
↳ replying to Nicolette
A) 0.00135
LA
Laurel 1 year ago
Hmm, this seems like a tricky one. I'm going to have to think through this carefully.
YV
Yvette 1 year ago
I'm not sure, but I think the correct answer might be D) 0.1362
GR
Gregoria 2 years ago
I agree with Peggy, because the probability of falling outside the control limits is relatively low at 0.0681
PE
Peggy 2 years ago
I think the answer is C) 0.0681
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