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ASQ CSSBB Exam - Topic 10 Question 97 Discussion

Actual exam question for ASQ's CSSBB exam
Question #: 97
Topic #: 10
[All CSSBB Questions]

An x-bar and R chart has four part measurements per sample The control limits on the averages chart are 2.996 and 3.256. Assume the process data form a normal distribution.What is the probability that the next part measurement falls outside the control limits?

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Suggested Answer: C

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Ruby
3 months ago
Yeah, I agree with A, seems right to me!
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Wilda
3 months ago
Wait, are we sure about the normal distribution assumption?
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Dianne
3 months ago
Definitely not E, that seems way too high.
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Royce
4 months ago
I think the probability is pretty low, maybe A?
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Rozella
4 months ago
The control limits are 2.996 and 3.256.
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Frederick
4 months ago
I feel like the answer might be around 0.0027, but I’m not confident. I should have practiced more with these types of problems.
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Evette
4 months ago
If the process is normally distributed, I believe the area outside the control limits is what we need to find, but I can't recall the exact method.
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Kristeen
4 months ago
I remember a similar question where we had to find the probability of falling outside control limits, and I think it involved using the normal distribution table.
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Marya
5 months ago
I think we need to calculate the z-scores for the control limits, but I'm not entirely sure how to do that with the averages.
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Cristina
5 months ago
Alright, let's think this through step-by-step. I need to find the z-score corresponding to the control limits, then use a normal distribution table to get the probability. I've got a good strategy here.
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Troy
5 months ago
Wait, is this a one-tailed or two-tailed probability? I better double-check the question to make sure I'm interpreting it correctly. Don't want to mess this up.
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Layla
5 months ago
This seems straightforward enough. I just need to plug the given control limits into the standard normal distribution formula and calculate the probability. I've got this!
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Kate
5 months ago
Hmm, I'm a bit confused about the normal distribution assumption here. Do I need to standardize the data before calculating the probability? I'll have to review that part.
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Kanisha
5 months ago
Okay, this looks like a probability question involving an x-bar and R chart. I'll need to remember the formulas for calculating the control limits and the probability of a part measurement falling outside those limits.
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Reuben
5 months ago
I've got this! Based on the weight of 9kg and price of 10, the expected result is C - no need to pay in cash, free delivery. The decision tables clearly show that for items under 10kg and under 20, free delivery is provided.
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Hubert
9 months ago
Alright, time to put on my best poker face and make an educated guess. Here goes nothing!
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Tamie
8 months ago
D) 0.1362
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Noelia
8 months ago
C) 0.0681
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Yuriko
8 months ago
B) 0.0027
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Leatha
8 months ago
A) 0.00135
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Edwin
10 months ago
I'm feeling a little like a mad scientist trying to solve this problem. Where's my lab coat when I need it?
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Dalene
8 months ago
C) 0.0681
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Josephine
8 months ago
B) 0.0027
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Laila
9 months ago
A) 0.00135
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Nicolette
10 months ago
Oooh, I think I know this one! Let me work it out step-by-step.
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Stefan
9 months ago
C) 0.0681
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Madalyn
9 months ago
B) 0.0027
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Elin
9 months ago
A) 0.00135
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Laurel
10 months ago
Hmm, this seems like a tricky one. I'm going to have to think through this carefully.
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Yvette
10 months ago
I'm not sure, but I think the correct answer might be D) 0.1362
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Gregoria
11 months ago
I agree with Peggy, because the probability of falling outside the control limits is relatively low at 0.0681
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Peggy
11 months ago
I think the answer is C) 0.0681
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