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SAS Exam A00-240 Topic 10 Question 93 Discussion

Actual exam question for SAS's A00-240 exam
Question #: 93
Topic #: 10
[All A00-240 Questions]

Refer to the confusion matrix:

Calculate the sensitivity. (0 - negative outcome, 1 - positive outcome)

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Suggested Answer: A

Contribute your Thoughts:

Sarina
13 days ago
Is there a lifeline I can use? I'm drawing a complete blank here!
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Luann
15 days ago
Wait, is this a trick question? What if the real answer is just 'yes'?
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Bernardo
20 days ago
Sensitivity, huh? I'm just going to guess and say A) 25/48. What could go wrong?
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Cristen
25 days ago
Hmm, the sensitivity is the true positive rate, so it's the number of true positives divided by the total number of actual positives. I'm going with D) 58/81.
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Estrella
9 days ago
So, the sensitivity is calculated by dividing the number of true positives by the total actual positives.
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Stephaine
18 days ago
Yes, it's important to correctly identify the true positives in the confusion matrix.
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Tawna
20 days ago
I think you're right, the sensitivity is indeed the true positive rate.
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Wayne
1 months ago
Oh, this is tricky! Let me think about this... Okay, I'm going to go with B) 58/102.
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User 3: Yes, that's correct. B) 58/102 is the sensitivity in this case.
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Solange
15 days ago
User 2: So, the sensitivity would be 58/102 then?
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Tamar
21 days ago
User 1: I think the sensitivity is calculated by dividing the true positive by the sum of true positive and false negative.
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Margarett
1 months ago
Sensitivity is the proportion of actual positives that are correctly identified as positive. I think the correct answer is D) 58/81.
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Kimi
1 months ago
I agree, the sensitivity is calculated as the true positives divided by the sum of true positives and false negatives.
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Sheron
2 months ago
I'm not sure about the calculation. Can someone explain why the sensitivity is 25/48?
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Detra
2 months ago
I agree with Noel. So, the correct answer should be A) 25/48.
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Noel
2 months ago
I think the sensitivity is calculated by dividing the true positive by the sum of true positive and false negative.
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