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SAP C_ABAPD_2507 Exam - Topic 1 Question 4 Discussion

Actual exam question for SAP's C_ABAPD_2507 exam
Question #: 4
Topic #: 1
[All C_ABAPD_2507 Questions]

Exhibit:

With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts? Note:

There are 2 correct answers to this question

Show Suggested Answer Hide Answer
Suggested Answer: A, D

The following are the explanations for each statement:

A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is not possible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super.Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12

B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception.However, the CAST operator will not work for go_subl, as explained in statement A12

C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super.Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123

D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass-specific method of cl_subl, which is not inherited by cl_super.Therefore, the method call go_subl->subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123


by Nikita at Aug 04, 2025, 02:16 AM

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Delpha
1 month ago
I disagree, I thought A would work too.
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Carey
2 months ago
Wait, how can B and C both be correct?
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Felice
2 months ago
B seems right, but I'm not sure about C.
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Carmela
2 months ago
A won't work, that's for sure.
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Michal
3 months ago
I think D is definitely correct!
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Theresia
3 months ago
For option D, I think it should work since we're calling a method specific to the subclass. But I'm not 100% confident about the casting part.
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Mayra
3 months ago
I'm not entirely sure about option C. I think it mentions something about the method working, but I can't recall if the cast itself would fail.
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Mitzie
4 months ago
I feel like I saw a similar question in our practice tests. I think option B could be right because casting to the subclass should work if it's from the superclass.
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Kathrine
4 months ago
I remember that casting from a superclass to a subclass can be tricky. I think option A might be correct since it sounds like it won't work.
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Cherry
4 months ago
Alright, I think I've got a handle on this. Time to carefully evaluate each of the answer choices and see which ones are correct.
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Glennis
4 months ago
I think the key is to focus on the specific casting operations mentioned and how they will or won't work based on the inheritance structure. Gotta be careful with those subclass-specific methods.
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Keshia
4 months ago
I'm a bit confused by the wording of the question. I'll need to re-read it a few times and maybe draw out the class diagram to visualize the relationships.
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Josphine
5 months ago
Okay, let me see if I can break this down step-by-step. The key seems to be understanding how the casting works between the superclass and subclasses.
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Kristel
5 months ago
Hmm, this looks like a tricky question about casting and method calls. I'll need to think carefully about the inheritance hierarchy and method access to figure this out.
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Alline
5 months ago
Ooh, this is a real head-scratcher. I'm gonna go with B, but only because I like the sound of 'go_sub2' more than 'go_subl'. Gotta go with the cooler-sounding option, you know?
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Julieta
5 months ago
Wait, there are two correct answers? This must be one of those tricky questions where the answer is 'all of the above' or 'none of the above'. I'm going with C just to be safe.
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Wilda
2 months ago
I guess we’ll find out soon enough!
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Viola
2 months ago
What if both A and B are correct? That would be wild!
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Sharan
3 months ago
I think it's definitely tricky! But I feel like A might be right too.
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Arlette
3 months ago
I’m leaning towards B. It just seems more logical to me.
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Veta
5 months ago
I think the correct answers are B and D.
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Ronna
7 months ago
D all the way, baby! If I can call the subclass-specific method directly, I'm golden. Who needs all that fancy casting nonsense?
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Dierdre
5 months ago
D all the way, baby! If I can call the subclass-specific method directly, I'm golden. Who needs all that fancy casting nonsense?
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Carin
7 months ago
Hmm, I think option B is the way to go. Casting to the superclass should work, but casting to the subclass-specific methods? Nah, that's a no-go.
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