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Nokia 4A0-107 Exam - Topic 3 Question 62 Discussion

Actual exam question for Nokia's 4A0-107 exam
Question #: 62
Topic #: 3
[All 4A0-107 Questions]

Assume all transmitted frames on a SONET port are 1500 bytes and that the average frame overhead has been configured as 10%. If the total bandwidth of all queues, excluding overhead, needs to be guaranteed at 55 Mbps, how much bandwidth should be configured for the egress port scheduler applied on that port?

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Suggested Answer: D

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Dylan
5 months ago
Gotta go with option C, seems right to me!
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Cyril
5 months ago
Isn't it just 55 Mbps? Why add more?
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Roosevelt
5 months ago
Wait, how does 55 Mbps plus overhead equal 60 Mbps?
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Tequila
5 months ago
I think option A makes the most sense here.
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Deangelo
6 months ago
The overhead is 10%, so we need to account for that.
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Noe
6 months ago
I vaguely remember that we need to account for the 10% overhead, so it seems like we should be looking at something like 60 Mbps, but I'm not confident.
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Beckie
6 months ago
I feel like the answer should be higher than 55 Mbps because of the overhead, but I can't recall the exact formula we used in class.
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Ariel
6 months ago
I think we practiced a similar question where we had to account for overhead percentages. Maybe it's about dividing the guaranteed bandwidth by the effective rate?
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Jamal
6 months ago
I remember something about calculating bandwidth with overhead, but I'm not sure if I should just add the overhead directly or adjust it somehow.
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Karon
6 months ago
This seems straightforward. The question states the total bandwidth, excluding overhead, needs to be 55 Mbps. So we just need to configure the port scheduler for 55 Mbps.
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Mi
6 months ago
I think the answer is C. We need to add the overhead to the 55 Mbps, so 55 Mbps + (55 Mbps * 0.1) = 60 Mbps.
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Chandra
6 months ago
Okay, let's think this through step-by-step. We need to account for the 10% overhead, so we'll need to configure the port scheduler for a higher bandwidth than the 55 Mbps we need to guarantee.
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Dorathy
7 months ago
Hmm, I'm a bit confused. Do we need to add the overhead to the 55 Mbps, or divide the 55 Mbps by 1.1 to get the actual bandwidth we need to configure?
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Cruz
7 months ago
I'm pretty confident I know this one. The Oracle instance is a combination of the database files, parameter file, and background processes.
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Lizbeth
7 months ago
I think enterprise networking products mostly include WAN and LAN, right? They seem essential for connectivity.
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Miles
7 months ago
I've got it! The file will inherit the destination folder's permissions, so the correct answer is C.
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Deandrea
12 months ago
This question is like a bad joke. It's asking me to configure the bandwidth higher than the actual requirement. I bet the test writer is having a good laugh at our expense.
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Gerald
11 months ago
Yeah, it's all about making sure you understand the requirements and not falling for the trick answers.
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Marnie
11 months ago
I think the key is to remember to account for the overhead in the calculation.
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Tonette
11 months ago
I know, it's frustrating when the question seems tricky like that.
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Lorrine
12 months ago
Okay, let me think this through. If I factor in the 10% overhead, that's gotta be the answer. *scratches head* Wait, which one was it again?
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Gerardo
11 months ago
C) 55 Mbps + 55 Mbps * 0.1 / 1.1 = 60 Mbps
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Nobuko
11 months ago
Yes, that's correct. The answer is C) 55 Mbps + 55 Mbps * 0.1 / 1.1 = 60 Mbps
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Gilberto
11 months ago
I think it's C) 55 Mbps + 55 Mbps * 0.1 / 1.1 = 60 Mbps
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Ciara
11 months ago
C) 55 Mbps + 55 Mbps * 0.1 / 1.1 = 60 Mbps
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Glory
11 months ago
B) 55 Mbps
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Meghann
12 months ago
A) 55 Mbps / 1.1 = 50 Mbps
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Noah
12 months ago
A) 55 Mbps / 1.1 = 50 Mbps
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Daren
12 months ago
Haha, classic exam trickery. They're trying to make us overthink this, but I'm not falling for it. I know the answer is C, 60 Mbps. Bring it on, certification gods!
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Matt
1 year ago
Wait, what? Did they really just throw in a 10% overhead factor? That's like trying to fit 55 Mbps into a 50 Mbps pipe. Good luck with that!
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Tayna
1 year ago
But if we consider the frame overhead, the answer should be C) 60 Mbps.
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Tawanna
1 year ago
Ah, the classic SONET port bandwidth conundrum. I bet the correct answer is hiding right under our noses.
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Cheryl
11 months ago
D) 55 Mbps * 1.1 = 60.5 Mbps
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Hyman
11 months ago
C) 55 Mbps + 55 Mbps * 0.1 / 1.1 = 60 Mbps
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Delisa
11 months ago
B) 55 Mbps
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Hoa
12 months ago
A) 55 Mbps / 1.1 = 50 Mbps
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Johanna
1 year ago
I disagree, I believe the correct answer is D) 60.5 Mbps.
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Tayna
1 year ago
I think the answer is A) 50 Mbps.
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