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Nokia 4A0-104 Exam - Topic 7 Question 67 Discussion

Posted by Linn on Jan 26, 2024 at 09:31 PM

What is the minimum Ethernet physical network MTU required for a Layer 2 service on a GRE encapsulated SDP with a service MTU of 1514?

Suggested Answer: C

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45 comments · newest first
BE
Berry 11 months ago
I disagree, I think it should be 1548 to be safe.
VI
Vincenza 11 months ago
Wait, is it really just 1526? That seems low for GRE.
CA
Carman 11 months ago
I thought it would be higher than that, but 1526 seems right.
OZ
Ozell 11 months ago
Definitely going with 1526 for the MTU. Makes sense!
GE
Gerald 12 months ago
The service MTU is 1514, so we need to account for GRE overhead.
AF
Afton 12 months ago
I practiced a similar question, and I think the minimum MTU should be 1526 to accommodate the GRE overhead.
CA
Carmen 1 year ago
I’m not entirely sure, but I feel like the answer could be 1548 since that’s a common value for GRE.
AZ
Azalee 1 year ago
I remember something about needing to account for the GRE header, which could mean we need at least 1526.
KA
Karan 1 year ago
I think the MTU for GRE encapsulation adds some overhead, so it might be higher than 1514.
ID
Idella 1 year ago
The key is understanding how GRE encapsulation affects the frame size. I'll work through the math step-by-step to determine the minimum required Ethernet MTU.
ST
Stefany 1 year ago
I'm a bit confused. Is the answer just the service MTU plus some additional overhead, or is there more to consider here?
NA
Natalya 1 year ago
Okay, I've got this. The service MTU is 1514, so the Ethernet physical network MTU needs to be larger to account for the GRE encapsulation.
OR
Oretha 1 year ago
Hmm, this is a tricky one. I'll need to think through the layers and encapsulation to figure out the right answer.
AG
Agustin 1 year ago
I'm pretty confident the answer is B. The GRE encapsulation adds 24 bytes, so the minimum Ethernet MTU would be 1514 + 24 = 1538, which rounds up to 1526.
LA
Lashaunda 1 year ago
Ah, the point-to-point interface configuration on Router1 could be the key. I'll focus on that and see if changing it to the correct setting resolves the issue.
KI
Kimbery 1 year ago
I'm a bit confused by this question. How exactly do user stories relate to the Fundamental Test Process? I'll have to review my notes on that.
JA
Jamie 1 year ago
Hmm, I'm a bit confused by the output options. Let me re-examine the code and the expected results.
KA
Kaitlyn 1 year ago
I'm stumped. Maybe I should just ask the network fairy for the answer. They always know this stuff, right?
RA
Rasheeda 1 year ago
↳ replying to Kaitlyn
I agree, the answer is A) 1514.
ME
Melvin 1 year ago
↳ replying to Kaitlyn
I think it's A) 1514.
ME
Melda 1 year ago
↳ replying to Kaitlyn
E) 1536
TO
Tonette 1 year ago
↳ replying to Kaitlyn
A) 1514
RA
Rachael 1 year ago
E, definitely E. 1536 bytes sounds like the perfect MTU for a Layer 2 service. Why? Because it's the magic number, that's why!
KA
Kallie 1 year ago
↳ replying to Rachael
I agree, E is the best choice. It aligns with the service MTU of 1514 for GRE encapsulated SDP.
TE
Tegan 1 year ago
↳ replying to Rachael
Yeah, E makes sense. It's the most common MTU size for Ethernet networks.
KR
Krystina 1 year ago
↳ replying to Rachael
I think E is the correct answer too. 1536 bytes is the standard MTU for Layer 2 services.
GA
Gabriele 1 year ago
D has got to be the right answer. I mean, who doesn't love adding 42 bytes to the Ethernet frame? Party on, Wayne!
LA
Lauran 1 year ago
↳ replying to Gabriele
D) 1556 seems like the best option to me.
GL
Glenna 1 year ago
↳ replying to Gabriele
I believe E) 1536 is the right choice.
JO
Joye 1 year ago
↳ replying to Gabriele
I'm going with E) 1536, seems like the best choice.
KA
Kaycee 1 year ago
↳ replying to Gabriele
No way, it's definitely B) 1526.
JE
Jerry 1 year ago
↳ replying to Gabriele
I think A) 1514 is the correct answer.
LA
Lavonna 1 year ago
↳ replying to Gabriele
I think A) 1514 is the correct answer.
WE
Werner 1 year ago
Hmm, this looks tricky. I'm going to go with C. Gotta love those extra 22 bytes for the GRE header!
ME
Melodie 2 years ago
I'm pretty sure the answer is B. The service MTU is 1514, and we need to account for the GRE encapsulation overhead.
SO
Sonia 1 year ago
↳ replying to Melodie
Let's double check the calculations to be sure.
NA
Nana 1 year ago
↳ replying to Melodie
No, I'm confident it's B) 1526.
GE
Gerald 1 year ago
↳ replying to Melodie
Are you sure? I believe it's E) 1536.
DE
Desirae 1 year ago
↳ replying to Melodie
I think the answer is B) 1526.
DA
Dana 2 years ago
But the service MTU is 1514, so the minimum Ethernet physical network MTU required should be higher than that. That's why I think it's E) 1536.
AN
Annamaria 2 years ago
I disagree, I believe the answer is B) 1526.
DA
Dana 2 years ago
I think the answer is E) 1536.
KE
Kelvin 2 years ago
I agree with Georgeanna, the answer is E) 1536 because the Ethernet physical network MTU needs to accommodate the service MTU of 1514 plus the GRE encapsulation overhead.
RE
Regenia 2 years ago
I believe the correct answer is B) 1526.
GE
Georgeanna 2 years ago
I think the answer is E) 1536.
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