Nokia 4A0-104 Exam - Topic 7 Question 67 Discussion

Actual exam question for Nokia's 4A0-104 exam

Question #: 67
Topic #: 7

What is the minimum Ethernet physical network MTU required for a Layer 2 service on a GRE encapsulated SDP with a service MTU of 1514?

A1514

B1526

C1548

D1556

E1536

Show Suggested Answer

Suggested Answer: C

by Linn at Jan 26, 2024, 09:31 PM

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Berry

3 months ago

I disagree, I think it should be 1548 to be safe.

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Vincenza

3 months ago

Wait, is it really just 1526? That seems low for GRE.

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Carman

3 months ago

I thought it would be higher than that, but 1526 seems right.

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Ozell

4 months ago

Definitely going with 1526 for the MTU. Makes sense!

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Gerald

4 months ago

The service MTU is 1514, so we need to account for GRE overhead.

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Afton

4 months ago

I practiced a similar question, and I think the minimum MTU should be 1526 to accommodate the GRE overhead.

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Carmen

4 months ago

I’m not entirely sure, but I feel like the answer could be 1548 since that’s a common value for GRE.

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Azalee

4 months ago

I remember something about needing to account for the GRE header, which could mean we need at least 1526.

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Karan

5 months ago

I think the MTU for GRE encapsulation adds some overhead, so it might be higher than 1514.

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Idella

5 months ago

The key is understanding how GRE encapsulation affects the frame size. I'll work through the math step-by-step to determine the minimum required Ethernet MTU.

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Stefany

5 months ago

I'm a bit confused. Is the answer just the service MTU plus some additional overhead, or is there more to consider here?

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Natalya

5 months ago

Okay, I've got this. The service MTU is 1514, so the Ethernet physical network MTU needs to be larger to account for the GRE encapsulation.

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Oretha

5 months ago

Hmm, this is a tricky one. I'll need to think through the layers and encapsulation to figure out the right answer.

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Agustin

5 months ago

I'm pretty confident the answer is B. The GRE encapsulation adds 24 bytes, so the minimum Ethernet MTU would be 1514 + 24 = 1538, which rounds up to 1526.

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Lashaunda

5 months ago

Ah, the point-to-point interface configuration on Router1 could be the key. I'll focus on that and see if changing it to the correct setting resolves the issue.

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Kimbery

5 months ago

I'm a bit confused by this question. How exactly do user stories relate to the Fundamental Test Process? I'll have to review my notes on that.

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Jamie

5 months ago

Hmm, I'm a bit confused by the output options. Let me re-examine the code and the expected results.

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Kaitlyn

9 months ago

I'm stumped. Maybe I should just ask the network fairy for the answer. They always know this stuff, right?

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Rasheeda

8 months ago

I agree, the answer is A) 1514.

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Melvin

8 months ago

I think it's A) 1514.

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Melda

8 months ago

E) 1536

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Tonette

8 months ago

A) 1514

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Rachael

10 months ago

E, definitely E. 1536 bytes sounds like the perfect MTU for a Layer 2 service. Why? Because it's the magic number, that's why!

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Kallie

8 months ago

I agree, E is the best choice. It aligns with the service MTU of 1514 for GRE encapsulated SDP.

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Tegan

8 months ago

Yeah, E makes sense. It's the most common MTU size for Ethernet networks.

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Krystina

8 months ago

I think E is the correct answer too. 1536 bytes is the standard MTU for Layer 2 services.

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Gabriele

10 months ago

D has got to be the right answer. I mean, who doesn't love adding 42 bytes to the Ethernet frame? Party on, Wayne!

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Lauran

8 months ago

D) 1556 seems like the best option to me.

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Glenna

8 months ago

I believe E) 1536 is the right choice.

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Joye

9 months ago

I'm going with E) 1536, seems like the best choice.

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Kaycee

9 months ago

No way, it's definitely B) 1526.

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Jerry

9 months ago

I think A) 1514 is the correct answer.

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Lavonna

9 months ago

I think A) 1514 is the correct answer.

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Werner

10 months ago

Hmm, this looks tricky. I'm going to go with C. Gotta love those extra 22 bytes for the GRE header!

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Melodie

10 months ago

I'm pretty sure the answer is B. The service MTU is 1514, and we need to account for the GRE encapsulation overhead.

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Sonia

9 months ago

Let's double check the calculations to be sure.

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Nana

10 months ago

No, I'm confident it's B) 1526.

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Gerald

10 months ago

Are you sure? I believe it's E) 1536.

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Desirae

10 months ago

I think the answer is B) 1526.

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Dana

10 months ago

But the service MTU is 1514, so the minimum Ethernet physical network MTU required should be higher than that. That's why I think it's E) 1536.

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Annamaria

10 months ago

I disagree, I believe the answer is B) 1526.

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Dana

10 months ago

I think the answer is E) 1536.

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Kelvin

10 months ago

I agree with Georgeanna, the answer is E) 1536 because the Ethernet physical network MTU needs to accommodate the service MTU of 1514 plus the GRE encapsulation overhead.

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Regenia

11 months ago

I believe the correct answer is B) 1526.

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Georgeanna

11 months ago

I think the answer is E) 1536.

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