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Netskope Exam NSK300 Topic 6 Question 26 Discussion

Actual exam question for Netskope's NSK300 exam
Question #: 26
Topic #: 6
[All NSK300 Questions]

You built a number of DLP profiles for different sensitive data types. If a file contains any of this sensitive data, you want to take the most restrictive policy action but also create incident details for all matching profiles.

Which statement is correct in this scenario?

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Contribute your Thoughts:

Rodrigo
20 days ago
Wait, so we're supposed to choose the most restrictive policy that also creates the most incidents? Sounds like a real party trick! I'm going with the option that lets me juggle the most balls at once.
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Delisa
23 days ago
Option B is the way to go. I don't want to deal with a bunch of separate incidents, that's just going to be a headache. A single incident with all the matches is the way to go.
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Natalya
26 days ago
Option D is the answer for me. Why create multiple policies when you can have everything in one place? Plus, a single incident is easier to manage and report on.
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Shawnda
8 days ago
Option D is definitely the way to go. It keeps everything organized and makes reporting simpler.
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Katlyn
1 months ago
I'm leaning towards Option C. Having a single policy with all the DLP profiles seems more efficient, and the unique incidents will give me better visibility.
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Loreen
9 days ago
It definitely seems like the most efficient way to handle sensitive data incidents.
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Denae
20 days ago
I agree, having all the DLP profiles in one policy will streamline the process.
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Dorothy
21 days ago
Option C sounds like the best choice. It will make managing incidents easier.
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Ceola
1 months ago
Option A sounds like the way to go. I like the idea of creating a unique incident for each matched profile. It'll make it easier to track and investigate each incident separately.
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Shannon
2 months ago
But having a single policy for all profiles might make it harder to track incidents.
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Cristen
2 months ago
I disagree, I believe the answer is D.
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Shannon
2 months ago
I think the correct statement is C.
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