Microsoft AZ-104 Exam - Topic 4 Question 70 Discussion

Actual exam question for Microsoft's AZ-104 exam

Question #: 70
Topic #: 4

You have an on-premises network.

You have an Azure subscription that contains three virtual networks named VNET1, VNET2, and VNET3. The virtual networks are peered and connected to the on-premises network. The subscription contains the virtual machines shown in the following table.

You need to monitor connectivity between the virtual machines and the on-premises network by using Connection Monitor. What is the minimum number of connection monitors you should deploy?

Show Suggested Answer

Suggested Answer: B

by Glory at Dec 11, 2022, 12:46 PM

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Catalina

4 months ago

Not sure about that, seems too simple for such a complex network.

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Donette

4 months ago

Definitely 1, it can monitor multiple VMs at once.

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Maybelle

4 months ago

Wait, really? I thought we needed one for each VM.

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Tamar

4 months ago

I think 2 would be safer, just to cover all bases.

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Leigha

5 months ago

You only need 1 connection monitor for this setup.

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An

5 months ago

I'm a bit confused; could it be just one monitor if they are all peered? I need to double-check that concept.

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Lindsey

5 months ago

I practiced a similar question, and I think the answer might be three because we need to cover all the VMs effectively.

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Rosendo

5 months ago

I think we might need at least two monitors since we have multiple VMs across different networks.

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Curtis

5 months ago

I remember something about needing one connection monitor per virtual network, but I'm not sure if that's the case here.

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Kimberely

5 months ago

Hmm, this is a tricky one. I'm not entirely sure which option to choose here. I know expressions can be used to evaluate conditions, but I'm not confident that's the right answer. I might need to review the Power Automate documentation to be sure.

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Lorriane

5 months ago

I've got this! A HIPS is all about monitoring and protecting the individual host, not the network. So it can't detect events scattered across the network, making statement A false. And it's not related to IP address sharing, so statement B is also false.

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