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IFPUG I40-420 Exam - Topic 2 Question 68 Discussion

Which of the following rules would apply when counting FTRs for an EI?
D) None of the above
A) Count one FTR for each unique data function that is accessed
B) Count one FTR for each transactional function read during the processing of the EI
C) Count two FTRs for each unique data function that is both maintained and read

IFPUG I40-420 Exam - Topic 2 Question 68 Discussion

Actual exam question for IFPUG's I40-420 exam
Question #: 68
Topic #: 2
[All I40-420 Questions]

Which of the following rules would apply when counting FTRs for an EI?

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Suggested Answer: D

by Golda at Apr 20, 2023, 12:52 PM

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Jordan
10 months ago
Wait, are we really counting two FTRs for maintained and read? That seems off!
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Elouise
10 months ago
I disagree with D, there are valid options here!
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Lashandra
10 months ago
C is definitely a thing, but it feels a bit complicated.
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Della
11 months ago
I think B makes more sense for transactional functions.
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Svetlana
11 months ago
A is correct, count one FTR for each unique data function.
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Kiley
11 months ago
I'm leaning towards D because none of the options seem to fit what we learned about counting FTRs, but I could be wrong.
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Glendora
11 months ago
I practiced a similar question where we had to decide between counting FTRs for read and maintain functions, and I think it was two for both, which might relate to option C.
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Kaycee
11 months ago
I feel like option B sounds familiar since it mentions transactional functions, but I can't recall the specifics about how we count those.
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Brock
11 months ago
I think I remember that we count FTRs based on unique data functions, but I'm not sure if it's just one for each or if there are exceptions.
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Mari
11 months ago
I've got this! Service confirmation, contract, and inbound delivery are the three correct answers. I'm feeling confident about this one.
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Rory
11 months ago
Okay, I think I understand this now. We need to find the present value of the $15,000 in 2 years, given the 12% interest rate compounded quarterly.
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Michel
11 months ago
Based on the requirement to transport multiple payload types, I think VXLAN or GENEVE would be the most suitable options. I'll need to weigh the pros and cons of each to determine the best fit.
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Carrol
1 year ago
If I had a dollar for every time I saw a 'None of the above' option on a test, I'd be a millionaire by now. Come on, people, let's get creative!
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Tricia
1 year ago
Haha, 'None of the above'? Really? That's a cop-out answer if I ever saw one. I'm going with C.
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Chau
1 year ago
Option A sounds like the most straightforward answer to me. Why overcomplicate things?
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Tegan
1 year ago
I see your point, but I still think option A is the best choice.
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Johnetta
1 year ago
In that case, option C would apply, as it counts two FTRs.
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Mozell
1 year ago
But what if the data function is both maintained and read?
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Crista
1 year ago
I agree, option A seems like the simplest choice.
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Titus
1 year ago
Hmm, I'm not sure about this one. I was thinking option B, but now I'm second-guessing myself.
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Amie
1 year ago
User 3: I think it might be C) Count two FTRs for each unique data function that is both maintained and read
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Trevor
1 year ago
User 2: I'm not sure, I was leaning towards B) Count one FTR for each transactional function read during the processing of the EI
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Willard
1 year ago
User 1: I think it's A) Count one FTR for each unique data function that is accessed
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Catherin
1 year ago
I think option C is the correct answer. It makes sense to count two FTRs for data functions that are both maintained and read.
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Anjelica
1 year ago
I think option A might also be a valid rule to consider when counting FTRs for an EI.
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Valentin
1 year ago
I agree, option C does seem like the most logical choice.
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Jerilyn
1 year ago
I'm not sure, but I think the answer might be B) Count one FTR for each transactional function read during the processing of the EI.
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Yan
1 year ago
I disagree, I believe the answer is C) Count two FTRs for each unique data function that is both maintained and read.
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Markus
1 year ago
I think the answer is A) Count one FTR for each unique data function that is accessed.
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