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Determinewhich of the following is the Maclaurin expansion (up to the second order term) of: e2x
Suggested Answer: D
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12 comments · newest first
DA
Dana
11 months ago
I thought it would have more terms, interesting!
LI
Lili
12 months ago
I think Option B looks correct too!
SH
Shayne
12 months ago
Wait, are you sure about that? Seems too simple.
TA
Tanja
12 months ago
Totally agree, that’s the right expansion!
RO
Roy
1 year ago
The Maclaurin expansion of e^(2x) is 1 + 2x + 2x².
BA
Barrett
1 year ago
I think the answer should include the constant term and the linear term, but I’m not confident about the second-order term. I hope I remember the right formula!
CA
Casandra
1 year ago
I remember practicing a similar question where we had to find the expansion for sin(x). I think the second-order term is crucial here, but I can't recall the exact coefficients for e^(2x).
GL
Glory
1 year ago
I think the Maclaurin series for e^x is just the sum of the derivatives at zero, but I'm not sure how to apply it to e^(2x).
CA
Cassandra
1 year ago
I feel like I might be mixing up the coefficients for the terms. Is it just 1 and 2 for the first two terms, or do we need to consider something else?
CH
Charlette
1 year ago
I think I've got a good handle on this question. The key is to identify the correct statements about the Message Service (MS) service.
SI
Simona
1 year ago
I'm not so sure about B, I remember reading about ACLs but I'm not clear if they can enforce encryption directly.
KE
Keva
1 year ago
Hmm, this looks tricky. I'll need to carefully trace the code to see how the loop and the decrement operator are working.