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IBM C1000-088 Exam - Topic 8 Question 12 Discussion

Actual exam question for IBM's C1000-088 exam
Question #: 12
Topic #: 8
[All C1000-088 Questions]

A customer has requested a solution to support home directory sharing and they have an estimated 6800 NFS connections. What is the minimum recommended number of protocol nodes?

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Suggested Answer: A

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Armando
4 months ago
I disagree, 1 node is way too risky for 6800 connections.
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Theola
4 months ago
Wait, are we really sure about needing 4? Seems high!
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Gerald
4 months ago
Definitely need at least 2 for reliability.
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Michell
4 months ago
3 should be enough, right?
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Mollie
5 months ago
I think 4 nodes is the way to go for that many connections.
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Rusty
5 months ago
I’m torn between 2 and 3. I know we need redundancy, but I can't remember the exact calculations we did in class.
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Frederica
5 months ago
I vaguely recall that the number of nodes should be higher than the number of connections divided by a certain threshold. Could it be 4?
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Miesha
5 months ago
I think I practiced a similar question where we had to calculate nodes based on connections. I feel like 3 might be a safe bet.
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Andree
5 months ago
I remember something about scaling NFS connections, but I'm not sure if 2 nodes would be enough for 6800 connections.
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Merlyn
5 months ago
I'm a bit confused by the options. I'm not sure if default protocols or default encryption would also be considered common vulnerabilities. I'll have to think this through.
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Dalene
5 months ago
I'm a little confused about the discount rate. Is that the company's cost of capital or some other rate? I'll need to make sure I'm using the right discount rate in my calculations.
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Farrah
5 months ago
I remember we practiced a similar question in class, and it was about adding vertices for dynamic constraints.
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