The refractive index n1 of the fiber core must be the Q of the cladding refractive Mo n2, which is a necessary condition for transmitting the optical signal in the optical fiber.
I remember practicing a question about total internal reflection, and I think it was related to how n1 must be greater than n2 for effective signal transmission.
I'm not sure I fully understand the relationship they're looking for. Maybe I should review my notes on optical fiber principles before attempting this question.
I got this! The refractive index of the core has to be greater than the refractive index of the cladding. That way, the light can be confined and transmitted through the fiber.
Hmm, I think the key here is that the core refractive index needs to be higher than the cladding refractive index. That's a necessary condition for total internal reflection and guiding the optical signal.
Reuben
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