A sample of size 600 is drawn from a population. The sample mean equals 329. The total width of the 99% confidence interval for the population mean is 893. The estimated population variance equals ________.
This question feels similar to one we practiced in class, where we had to derive variance from the confidence interval width. I think it involves dividing by the sample size.
This looks straightforward. We just need to plug in the values we're given and do the math. I'm confident I can work through this step-by-step and arrive at the correct answer.
Wait, what? I'm lost. How do we get from the confidence interval information to the population variance? I need to review my notes on this type of problem.
I've got this! We can use the formula for the 99% confidence interval: sample mean +/- (t-value * standard error). Rearranging this, we can solve for the population variance.
Hmm, I'm a bit confused on how to approach this. I know we need to use the formula for the confidence interval, but I'm not sure how to rearrange it to solve for the population variance.
Okay, let's think this through step-by-step. We have the sample size, sample mean, and the total width of the 99% confidence interval. We can use this information to calculate the population variance.
Frank
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