C++ Institute CPP Exam - Topic 9 Question 97 Discussion
What happens when you attempt to compile and run the following code?#include #include #include using namespace std;int main (){int t[] = {1, 2 ,3 ,4 ,5};vectorv1(t, t+5);dequed1;d1.assign(v1.end(), v1.begin());for(int i=0; i
C) compilation error in line 8
A) program outputs 5 4 3 2 1
B) program outputs 1 2 3 4 5
D) compilation error in line 10
E) segmentation fault runtime exception
C++ Institute CPP Exam - Topic 9 Question 97 Discussion
I'm pretty confident that the answer is A. The `assign()` function on the `deque` will copy the elements from the `vector` in reverse order, so the output should be 5 4 3 2 1.
Alright, let me walk through this step-by-step. The `vector` is initialized with the values 1, 2, 3, 4, 5. Then, the `deque` is assigned the elements of the `vector` in reverse order. So, I think the output will be 5 4 3 2 1.
Okay, let me see here. The code is trying to assign the elements of the `vector` to the `deque` in reverse order. I think the answer might be A, but I'm not 100% sure.
Hmm, this looks like a tricky one. I'll need to carefully read through the code and think about the behavior of the `deque` and `vector` data structures.
I'm a bit confused by the `assign()` function call on the `deque`. I'll need to double-check the documentation to make sure I understand how that works.
C'mon, this is a trick question, right? I mean, who writes code with `deque` and `vector` like that? Probably some mad scientist trying to break the laws of programming or something.
I'm gonna go with option B, 1 2 3 4 5. Seems like the most straightforward answer, and I don't see any obvious bugs in the code. Gotta love it when the solution is just that simple!
Francesco
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