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C++ Institute CPP Exam - Topic 3 Question 31 Discussion

What happens when you attempt to compile and run the following code?#include #include #include using namespace std;int main(){int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };vectorv(myints, myints+10);set s1(v.begin(),v.end());set s2(v.begin(), v.end());for(set::iterator i=s1.begin();i!= s1.end(); i++) {cout
C) program outputs: 0 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 0
A) program outputs: 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9
B) program outputs: 9 8 7 6 5 4 3 2 1 0 9 8 7 6 5 4 3 2 1 0
D) program outputs: 9 8 7 6 5 4 3 2 1 0 0 1 2 3 4 5 6 7 8 9

C++ Institute CPP Exam - Topic 3 Question 31 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 31
Topic #: 3
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vectorv(myints, myints+10);

set s1(v.begin(),v.end());

set > s2(v.begin(), v.end());

for(set::iterator i=s1.begin();i!= s1.end(); i++) {

cout<<*i<<" ";

}

for(set >::iterator i=s2.begin();i!= s2.end(); i++) {

cout<<*i<<" ";

}

cout<

return 0;

}

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Suggested Answer: C

Contribute your Thoughts:

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Tenesha
7 months ago
Definitely not A, that’s not how sets work!
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Phuong
7 months ago
Wait, why would it output 0 twice? That seems off.
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Nu
7 months ago
I think option B is correct.
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Hyun
8 months ago
It should output the numbers in descending order first.
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Luisa
8 months ago
The program uses a set and a vector.
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Desmond
8 months ago
This seems like a straightforward question about RBI program discrimination. I'd start by reviewing the key concepts around failure analysis, failure modes, and consequence analysis to determine the most appropriate approach.
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Allene
8 months ago
I think the answer is going to be a combination of steps. Probably creating a new base image with the right OS and reinstalling the View Agent with the Instant Clone Agent. Gotta make sure I get both of those right.
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