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C++ Institute CPP Exam - Topic 11 Question 111 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 111
Topic #: 11
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

template void print(T start, T end) {

while (start != end) {

std::cout << *start << " "; start++;

}

}

int main() {

string t1[] ={ "1", "2", "3", "4", "5", "6", "7", "8", "9", "10"};

list l1(t1, t1 + 10);

list l2(l1);

l2.reverse(); l1.splice(l1.end(),l2);

l1.unique();

print(l1.begin(), l1.end()); cout<

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: B

by Ciara at Jul 13, 2025, 05:39 PM

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Fausto
2 months ago
I’m surprised it doesn’t throw any errors!
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Chauncey
2 months ago
Definitely going with option D!
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Shay
2 months ago
I think it outputs 1 to 10 and then reverses.
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Daron
3 months ago
Wait, does it really handle duplicates correctly?
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Shenika
3 months ago
Looks like it should compile fine.
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Charisse
3 months ago
I think the output should just be "1 2 3 4 5 6 7 8 9 10" since `unique()` would remove any duplicates, but I'm not entirely sure if there are any duplicates after the operations.
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My
3 months ago
I feel like the output will include all the numbers from 1 to 10, but I'm not confident about what happens with the reversed list. Does `unique()` remove duplicates or just adjacent ones?
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Linn
4 months ago
I remember a practice question where we used `list::reverse()` and `list::splice()`, but I can't recall how they interact with `unique()`. Could it lead to duplicates in the output?
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Avery
4 months ago
I think the code should compile fine since all the includes and syntax look correct, but I'm not sure about the output after the splice and unique operations.
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Curtis
4 months ago
This seems straightforward enough. The code manipulates the lists in a pretty straightforward way, so I'm confident option C is the correct answer.
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Wilson
4 months ago
I'm a bit confused by the use of the print() function here. Does it just print the contents of the list? I'll need to double-check how that works before answering.
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Marge
4 months ago
Okay, I think I've got it. The code creates two lists, reverses one, and then appends it to the other. The unique() call at the end should remove any duplicate elements. I'll go with option C.
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Jaime
5 months ago
Hmm, the splice and reverse operations on the lists seem like they could lead to some interesting output. I'll have to think through the order of the operations.
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Micaela
5 months ago
This looks like a tricky one! I'll need to carefully step through the code to understand what's happening.
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Jimmie
6 months ago
I don't see any compilation errors in the code, so I'm sticking with option B.
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Lachelle
6 months ago
I'm not sure, but I think D) compilation error is also a possibility.
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Werner
6 months ago
This code is making my head spin. I feel like I need a degree in quantum physics just to understand what's going on here. Maybe the compiler will just throw up its hands and refuse to touch this mess.
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Kenny
7 months ago
Wait, are we sure the output will be in numeric order? Shouldn't it be 0 1 2 3 4 5 6 7 8 9 0 2 3 6 9 since the unique operation will only remove the first occurrence of each duplicate element?
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Santos
7 months ago
Hmm, I think there might be a compilation error. The code is using a template function to print the elements, but it's not clear if that will work with the string type. Maybe we need to specialize the template or something.
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Edwin
5 months ago
User2: Yeah, the code is using a template function with string type.
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Audry
6 months ago
User1: I think there might be a compilation error.
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Delmy
7 months ago
I agree with Jimmie, the code looks like it will output that sequence.
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Jimmie
7 months ago
I think the answer is B) program outputs: 0 1 2 3 4 5 6 7 8 9
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Goldie
7 months ago
I'm pretty sure the output will be 9 8 7 6 5 4 3 2 1 0. The reverse operation on l2 should give us the elements in reverse order, and then they get appended to l1.
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Delbert
7 months ago
No, the correct output is: 0 1 2 3 4 5 6 7 8 9
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Delbert
7 months ago
I think it will output: 0 1 2 3 4 5 6 7 8 9
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Crista
7 months ago
The program will output 0 1 2 3 4 5 6 7 8 9. The splice operation appends the reversed list l2 to the end of l1, and the unique operation removes the duplicate elements.
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Freeman
7 months ago
That's correct. The unique operation removes the duplicate elements.
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Freeman
7 months ago
B) program outputs: 0 1 2 3 4 5 6 7 8 9
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