C++ Institute CPA-21-02 Exam - Topic 2 Question 42 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 42
Topic #: 2

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main(){

int *i;

i = new int;

*i = 1.0 / 2 * 2 / 1 * 2 / 4 * 4;

cout << *i;

return 0;

}

AIt prints: 0

BIt prints: 1

CIt prints: 2

DIt prints: 0.5

Show Suggested Answer

Suggested Answer: C

by Tiffiny at Jul 13, 2025, 05:57 PM

Limited Time Offer

25%

Off

Get Premium CPA-21-02 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Latia

8 months ago

It's using integer division, so 1.0/2 is 0 in this case.

upvoted 0 times

...

Altha

9 months ago

Wait, how does it not print 0.5?

upvoted 0 times

...

Alana

9 months ago

It prints: 1

upvoted 0 times

...

Jamie

9 months ago

Definitely prints 1, no doubt!

upvoted 0 times

...

Beckie

9 months ago

I thought it would be 0.5 too, but I guess not?

upvoted 0 times

...

Matilda

9 months ago

I feel like it should print 1 because of how the operations are ordered, but I'm not completely confident about the precedence rules.

upvoted 0 times

...

Jeffrey

10 months ago

I practiced a similar question where the output was affected by type casting. I wonder if that applies here too.

upvoted 0 times

...

Cory

10 months ago

I remember something about integer division in C++. If I recall correctly, 1.0 / 2 would be treated as a double, but the result gets assigned to an int pointer.

upvoted 0 times

...

Alaine

10 months ago

I think the expression evaluates to an integer, so it might print 0 or 1. I'm not entirely sure how the division works here.

upvoted 0 times

...

Phung

10 months ago

I'm feeling pretty confident about this one. The expression looks straightforward, and I know integer division will truncate the result.

upvoted 0 times

...

Oretha

10 months ago

I'm a bit confused by the use of the pointer here. I'll need to make sure I understand how the dereference operator works in this context.

upvoted 0 times

...

Colby

11 months ago

Okay, I think I've got this. The key is that the expression is using integer division, so I expect the result to be an integer.

upvoted 0 times

...

Jesusa

11 months ago

Hmm, the expression seems a bit convoluted. I'll need to pay close attention to the order of operations and integer division.

upvoted 0 times

...

Shantell

11 months ago

This looks like a tricky one. I'll need to carefully work through the expression step-by-step to figure out the result.

upvoted 0 times

...

Kerrie

12 months ago

Haha, the code looks like it's performing some sort of cosmic dance with the numbers. I wonder what the output will be?

upvoted 0 times

...

Buddy

1 year ago

Ooh, this looks like a trick question. I'm going to go with D just to be safe.

upvoted 0 times

...

Marylyn

1 year ago

Hmm, let me think about this... Doesn't integer division always truncate the result? I'm going with B!

upvoted 0 times

...

Pearly

1 year ago

Wait, are we supposed to use floating-point arithmetic or integer arithmetic? I'm so confused!

upvoted 0 times

...

Lorriane

1 year ago

That makes sense, I can see how the calculations would lead to that result

upvoted 0 times

...

Willodean

1 year ago

I think the correct answer is C) It prints: 2 because of the arithmetic operations in the code

upvoted 0 times

...

Dortha

1 year ago

But doesn't the code involve some calculations that might result in a different output?

upvoted 0 times

...

Lorriane

1 year ago

I believe the answer is B) It prints: 1

upvoted 0 times

...

Dortha

1 year ago

I think the answer is A) It prints: 0

upvoted 0 times

...