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Arista ACE-P-ALE1.04 Exam - Topic 3 Question 108 Discussion

Actual exam question for Arista's ACE-P-ALE1.04 exam
Question #: 108
Topic #: 3
[All ACE-P-ALE1.04 Questions]

In bash scripting, which of the following is NOT valid way of evaluating an arithmetic expression?

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Suggested Answer: C

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Altha
3 months ago
I've used let and $(( )) before, they work great!
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Dottie
3 months ago
A, C, and D are all valid methods.
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Alexia
4 months ago
Wait, are we sure about B?
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Brice
4 months ago
Totally agree, B doesn't work for that.
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Annette
4 months ago
I think B is not valid for arithmetic.
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Edelmira
4 months ago
I feel like ${} is used for variable expansion, not arithmetic, but I could be mixing it up.
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Rutha
5 months ago
I practiced a similar question, and I believe let is valid, so it must be one of the others.
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Cecily
5 months ago
I think $[] is the one that doesn't work for arithmetic, but I can't recall exactly why.
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Samuel
5 months ago
I remember using $(( )) for arithmetic, but I'm not sure about ${}.
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Hillary
5 months ago
Okay, let me think this through step-by-step. I know $(()), let, and even the command substitution $(command) can be used. But I don't recall ever seeing the ${} syntax used for arithmetic evaluation. I'll go with that as the invalid option.
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Lyndia
5 months ago
Ah, I remember learning about this in class. The $[] syntax is not a valid way to evaluate arithmetic expressions in Bash. I'm confident that's the correct answer.
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Sheron
5 months ago
Hmm, I'm a bit unsure about this one. I know we can use $(()), but I'm not familiar with the $[] syntax. I'll have to think this through carefully.
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Lakeesha
5 months ago
I'm pretty sure the ${} option is not a valid way to evaluate arithmetic expressions in Bash. I'll focus on the other choices and try to eliminate the invalid ones.
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