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XML I10-002 Exam - Topic 3 Question 36 Discussion

Push the Exhibit Button to load the referenced "testml.xsd".Assume that "testml.xsd" is defined. Without rewriting this XML Schema Document ("testml.xsd"), create a new, separate XML Schema Document to partially change the schema definition to write a cell Phone element as a child element of the person element. As a result, the following "XML Document" will be valid against the new schema. Which of the following correctly describes the new XML Schema Document? Assume the XML parser correctly processes the XML schema Location attribute.[XML.Documet]John Smith03-000-99900-1111-2222
C) <xs:schema xmlns:xs='http://www.w3.org/2001/XMLSchema'> <xs:redefine schemaLocation= ' testml.xsd ' > <xs:complexType name= ' personType ' > <xs:complexContent> <xs:extension base= ' personType ' > <xs:sequence> <xs:element ref= ' cellPhone ' /> </xs:sequence> </xs:extension> </xs:complexContent> </xs:complexType> </xs:redefine> <xs:element name= ' cellPhone ' type= ' xs:string ' /> </xs:schema>
A) <xs:schema xmlns:xs='http://www.w3.org/2001/XMLSchema'> <xs:import schemaLocation='testml.xsd' /> <xs:complexType name='personType'> <xs:sequence> <xs:element ref= ' name ' /> <xs:element ref= ' phone ' /> <xs:element ref= ' cellPhone ' /> </xs:sequence> </xs:complexType> <xs:element name= ' cellPhone ' type= ' xs:string ' /> </xs:schema>
B) <xs:schema xmlns:xs='http://www.w3.org/2001/XMLSchema'> <xs:include schemaLocation='testml.xsd' /> <xs:complexType name='newPersonType' substitutionGroup='personType'> <xs:sequence> <xs:element ref= ' name ' /> <xs:element ref= ' phone ' /> <xs:element ref= ' cellPhone ' /> </xs:sequence> </xs:complexType> <xs:element name= ' cellPhone ' type= ' xs:string ' /> </xs:schema>
D) It is not possible to implement a function of the type proposed.

XML I10-002 Exam - Topic 3 Question 36 Discussion

Actual exam question for XML's I10-002 exam
Question #: 36
Topic #: 3
[All I10-002 Questions]

Push the Exhibit Button to load the referenced "testml.xsd".

Assume that "testml.xsd" is defined. Without rewriting this XML Schema Document ("testml.xsd"), create a new, separate XML Schema Document to partially change the schema definition to write a cell Phone element as a child element of the person element. As a result, the following "XML Document" will be valid against the new schema. Which of the following correctly describes the new XML Schema Document? Assume the XML parser correctly processes the XML schema Location attribute.

[XML.Documet]

John Smith

03-000-999

00-1111-2222

Show Suggested Answer Hide Answer
Suggested Answer: C

by My at May 05, 2022, 10:07 PM

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Patrick
7 months ago
D doesn't sound right; it should be possible!
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Wilford
7 months ago
Wait, can you really redefine like that?
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Laquita
7 months ago
C seems a bit complicated for this.
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Delisa
8 months ago
I think B is the way to go.
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Linn
8 months ago
Option A looks good to me!
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Zachary
8 months ago
I can't recall if we covered the substitution group concept in detail, but option B seems interesting if it allows for new types under the same group.
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Maynard
8 months ago
I feel like option A is too simple; it doesn't really redefine the person type, which is what we need to do for the cellPhone element.
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Carylon
8 months ago
I think option C might be right because redefining the type seems to allow for adding new elements, but I'm not completely confident.
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Dacia
8 months ago
I remember we practiced a similar question about extending XML schemas, but I'm not sure if I should use import or include here.
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Lashaunda
8 months ago
This looks like a requirements.txt file, which is a common way to specify Python package dependencies. I'll review the file structure and contents to determine the correct answer.
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Margart
8 months ago
Hmm, this one seems tricky. I'll need to carefully review the code and the partial report to figure out why the labels aren't displaying.
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Ashton
8 months ago
I think A is correct about diversifying with different industries, but I'm not entirely sure about B. It seems too absolute to say systematic risk can be fully eliminated.
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