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WGU Applied Algebra Exam - Topic 2 Question 8 Discussion

The growth of an animal population is shown in the graph. The instantaneous rate of change at point is .Which interpretation of the instantaneous rate of change is correct?
C) In 2007, the population was increasing by 3,740 animals per year.
A) In 2012, the population was increasing by 3.74 animals per year.
B) In 2012, the population was increasing by 3,740 animals per year.
D) In 2007, the population was increasing by 3.74 animals per year.

WGU Applied Algebra Exam - Topic 2 Question 8 Discussion

Actual exam question for WGU's Applied Algebra exam
Question #: 8
Topic #: 2
[All Applied Algebra Questions]

The growth of an animal population is shown in the graph. The instantaneous rate of change at point is .

Which interpretation of the instantaneous rate of change is correct?

Show Suggested Answer Hide Answer
Suggested Answer: C

The graph shows population in thousands, and the horizontal axis represents:

Point is located at approximately:

Since represents years since 1995:

So point corresponds to the year:

The instantaneous rate of change at point is:

Because the vertical axis is measured in thousands, this means:

Convert thousands to actual animals:

So in 2007, the population was increasing by approximately:


by Adell at Jul 02, 2026, 10:42 AM

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Sang
I think we discussed that the instantaneous rate of change gives us the population growth at a specific year, but I can't recall which option matches that correctly.
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Afton
5 days ago
I feel like the rate of change should be in the same units as the population, so I’m leaning towards the smaller number, but I can't remember if it was 3.74 or 3,740.
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Shizue
10 days ago
I’m not entirely sure if the year is 2012 or 2007 for the rate of change. I think we had a similar question in practice where the year was crucial.
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Malinda
15 days ago
I remember we talked about how the instantaneous rate of change relates to the slope of the tangent line at a specific point on the graph.
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