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Splunk SPLK-2002 Exam - Topic 3 Question 64 Discussion

Actual exam question for Splunk's SPLK-2002 exam
Question #: 64
Topic #: 3
[All SPLK-2002 Questions]

An indexer cluster is being designed with the following characteristics:

* 10 search peers

* Replication Factor (RF): 4

* Search Factor (SF): 3

* No SmartStore usage

How many search peers can fail before data becomes unsearchable?

Show Suggested Answer Hide Answer
Suggested Answer: C

by Lonna at Jan 06, 2023, 09:03 AM

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Wilbert
7 months ago
One peer failing sounds too risky for me.
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Denny
7 months ago
No way, zero peers can fail!
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Rozella
7 months ago
Wait, can four really fail? That seems off.
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Joanna
7 months ago
Yeah, I agree with that!
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Sarah
7 months ago
I think three peers can fail before data is unsearchable.
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Kenneth
8 months ago
I’m confused about the relationship between RF and SF. If RF is 4, does that mean we can only afford to lose 3 peers? I’m leaning towards option C.
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Sharmaine
8 months ago
This question feels familiar. I practiced one where the RF was lower, and we could lose more peers. I think here, it might be just 1 peer that can fail safely.
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Andra
8 months ago
I’m not entirely sure, but I feel like the search factor of 3 means we can lose some peers without losing access. Maybe 3 peers can fail?
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Onita
8 months ago
I think I remember that with a replication factor of 4, we need at least 4 copies of the data to be available. So, if 4 peers fail, it might become unsearchable?
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Gerald
8 months ago
This question seems straightforward, I think I can identify the steps in Lewin's model of change pretty well.
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Lanie
8 months ago
I'm feeling pretty confident about this one. Based on my understanding, cloud-init provides its own startup mechanism that replaces the instance's original init system, so I'm going to go with option C.
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Cathern
8 months ago
This seems like a straightforward question about business continuity. I'll think through the options carefully and choose the one that best fits.
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Ben
1 year ago
Wait, so if four peers fail, we can still search? That's like trying to find a needle in a haystack, but the haystack is on fire. Good luck with that!
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Veronique
1 year ago
This is a tricky one, but I think the answer is B) One peer can fail. The replication factor of 4 means we need at least 3 peers to search, so if one peer fails, we're still good.
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Beckie
12 months ago
Yes, losing one peer out of 10 should still allow us to search the data without any issues.
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Glory
12 months ago
Good to know, thanks for clarifying!
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Dana
12 months ago
That makes sense, with a replication factor of 4 and a search factor of 3, we can afford to lose one peer.
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Deonna
12 months ago
That's correct, as long as only one peer fails, we can still search the data.
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Margo
12 months ago
I agree, the answer is B) One peer can fail.
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Noel
1 year ago
I agree, the answer is B) One peer can fail.
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Portia
1 year ago
I'm not sure about this one. The replication factor seems to be the key here, but I can't quite figure it out. I'll have to think about it some more.
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Darnell
11 months ago
D) Four peers can fail.
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Aleisha
11 months ago
C) Three peers can fail.
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Ressie
11 months ago
B) One peer can fail.
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Jaclyn
11 months ago
A) Zero peers can fail.
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Glendora
11 months ago
D) Four peers can fail.
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Merlyn
12 months ago
C) Three peers can fail.
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Huey
12 months ago
B) One peer can fail.
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Dyan
12 months ago
A) Zero peers can fail.
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Abel
1 year ago
Well, if 4 peers fail, that means we'd still have 6 peers left, which is above the search factor of 3, so I think D) Four peers can fail is the right choice.
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Joana
1 year ago
Hmm, let me think about this. With 10 search peers, a replication factor of 4, and a search factor of 3, I'd say that C) Three peers can fail is the correct answer.
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Denise
1 year ago
That makes sense, one peer can fail without affecting the searchability of the data.
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Rachael
1 year ago
I agree, C) Three peers can fail is the correct answer.
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Ettie
1 year ago
I'm not sure, but it makes sense that if we have 10 search peers and a Replication Factor of 4, we can tolerate losing three of them before data becomes unsearchable. So, I'll go with C) Three peers can fail.
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Jennifer
1 year ago
I agree with Paola, because with a Replication Factor of 4 and Search Factor of 3, we can afford to lose up to three search peers.
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Paola
1 year ago
I think the answer is C) Three peers can fail.
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