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Splunk SPLK-1002 Exam - Topic 6 Question 95 Discussion

Actual exam question for Splunk's SPLK-1002 exam
Question #: 95
Topic #: 6
[All SPLK-1002 Questions]

Which of these stats commands will show the total bytes for each unique combination of page and server?

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Suggested Answer: B

The correct command to show the total bytes for each unique combination of page and server isindex=web | stats sum (bytes) BY page server. In Splunk, thestatscommand is used to calculate aggregate statistics over the dataset, such as count, sum, avg, etc. When using theBYclause, it groups the results by the specified fields. The correct syntax does not include commas or the word 'AND' between the field names. Instead, it simply lists the field names separated by spaces within theBYclause.

Reference: The usage of thestatscommand with theBYclause is confirmed by examples in the Splunk Community, where it's explained thatstatswith aby foo barwill output one row for every unique combination of thebyfields1.


by Donte at Aug 23, 2024, 07:11 PM

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Graham
4 months ago
I thought it was A too, but I'm not 100% sure.
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Robt
5 months ago
Wait, D? That doesn't seem right at all!
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Johanna
5 months ago
C looks wrong to me, "AND" isn't used like that.
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Gilma
5 months ago
I think B makes more sense, though.
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Raylene
5 months ago
A is definitely the correct one!
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Emmanuel
6 months ago
Option D seems off to me; I don't remember using "values" like that in the context of stats.
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Marva
6 months ago
I feel like "AND" in option C is wrong; I don't recall seeing that used in stats commands before.
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Wei
6 months ago
I remember practicing a similar question, and I think "BY page server" in option B makes more sense for combining them.
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Dana
6 months ago
I think it's either A or B, but I'm not sure if "BY page BY server" is correct syntax.
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Ressie
6 months ago
I think option A is the way to go here. Grouping by both page and server, and then summing the bytes, seems like the clearest way to get the total bytes for each unique combination. The other options don't seem to capture that as directly.
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Denae
6 months ago
I'm a bit confused by the "BY values (page) values (server)" syntax in option D. I'm not sure how that would work compared to the more standard "BY page BY server" approach. I'll need to double-check the documentation on that one.
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Dorethea
6 months ago
Okay, let me walk through this step-by-step. I know I need to group the data by both page and server, and then sum the bytes. Option A looks like it does that, so I'm leaning towards that as the answer.
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Arlie
6 months ago
Hmm, I'm a little unsure about this one. The wording is a bit tricky. I'll need to carefully read through each option and think about how the stats command works to make sure I get this right.
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Mollie
6 months ago
This looks like a straightforward stats command question. I think option A is the correct answer - it groups the data by both page and server, and then sums the bytes for each unique combination.
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Jame
6 months ago
Okay, let me see here. The key thing to focus on is whether the counter variable is global or local to the enclosed scope activity. I think I have a good handle on this, so I'll give it my best shot.
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Elden
6 months ago
Okay, I think I've got this. The key is understanding the responsibilities of the composition sub-controller. If it can't enter that role when invoked by the initiator, then the answer must be True.
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Cecilia
2 years ago
I believe D) index=web | stats sum(bytes) BY values (page) values (server) is incorrect because it uses 'values' instead of 'BY'.
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Dortha
2 years ago
I'm not sure, but I think C) index=web | stats sum(bytes) BY page AND server might also work.
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Rory
2 years ago
Wait, is this a Splunk question? If so, I'm pretty sure A is the way to go. Gotta love those Splunk commands!
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Kanisha
1 year ago
B) index=web | stats sum (bytes) BY page server
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Johnna
2 years ago
Definitely! Splunk commands can be tricky, but A seems like the right choice.
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Quiana
2 years ago
A) index=web | stats sum (bytes) BY page BY server
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Devorah
2 years ago
Haha, I bet the person who wrote this question is a real stat-geek! But I'm still going with A.
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Edison
2 years ago
Let's go with A then.
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Mignon
2 years ago
I'm not sure, but A sounds logical.
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Darci
2 years ago
I agree, A seems like the right choice.
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Lai
2 years ago
I think A is the correct answer.
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Veta
2 years ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
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Tran
2 years ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
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Phil
2 years ago
B) index=web | stats sum (bytes) BY page server
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Marti
2 years ago
A) index=web | stats sum (bytes) BY page BY server
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Margot
2 years ago
I'm going with C. The 'AND' keyword makes it clear that we want to group by both page and server.
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Elin
2 years ago
C) index=web | stats sum(bytes) BY page AND server
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Marjory
2 years ago
A) index=web | stats sum (bytes) BY page BY server
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Willard
2 years ago
I agree with Sonia, because we need to show the total bytes for each unique combination of page and server.
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Rosendo
2 years ago
Option B looks good to me. It has the same grouping as A, but in a more concise way.
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Malcolm
2 years ago
I believe option A is the right choice because it specifically groups by page and server.
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Lorrie
2 years ago
I agree with you, option B seems more concise and still groups by both page and server.
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Louvenia
2 years ago
I think option A is the correct one. It groups by both page and server.
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Sonia
2 years ago
I think the answer is A) index=web | stats sum (bytes) BY page BY server.
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Malcolm
2 years ago
I think option A is the correct one. It groups the data by both page and server, which is what the question is asking for.
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Juan
2 years ago
Option D doesn't look right, it's using values instead of BY.
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King
2 years ago
I'm not sure about option C, it seems a bit off.
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Janet
2 years ago
I think option B might work too, it groups by both page and server.
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Portia
2 years ago
I agree, option A is the correct one.
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