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Splunk Exam SPLK-1002 Topic 6 Question 95 Discussion

Actual exam question for Splunk's SPLK-1002 exam
Question #: 95
Topic #: 6
[All SPLK-1002 Questions]

Which of these stats commands will show the total bytes for each unique combination of page and server?

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Suggested Answer: B

The correct command to show the total bytes for each unique combination of page and server isindex=web | stats sum (bytes) BY page server. In Splunk, thestatscommand is used to calculate aggregate statistics over the dataset, such as count, sum, avg, etc. When using theBYclause, it groups the results by the specified fields. The correct syntax does not include commas or the word 'AND' between the field names. Instead, it simply lists the field names separated by spaces within theBYclause.

Reference: The usage of thestatscommand with theBYclause is confirmed by examples in the Splunk Community, where it's explained thatstatswith aby foo barwill output one row for every unique combination of thebyfields1.


by Donte at Aug 23, 2024, 07:11 PM

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Cecilia
10 months ago
I believe D) index=web | stats sum(bytes) BY values (page) values (server) is incorrect because it uses 'values' instead of 'BY'.
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Dortha
10 months ago
I'm not sure, but I think C) index=web | stats sum(bytes) BY page AND server might also work.
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Rory
10 months ago
Wait, is this a Splunk question? If so, I'm pretty sure A is the way to go. Gotta love those Splunk commands!
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Kanisha
9 months ago
B) index=web | stats sum (bytes) BY page server
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Johnna
9 months ago
Definitely! Splunk commands can be tricky, but A seems like the right choice.
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Quiana
9 months ago
A) index=web | stats sum (bytes) BY page BY server
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Devorah
10 months ago
Haha, I bet the person who wrote this question is a real stat-geek! But I'm still going with A.
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Edison
9 months ago
Let's go with A then.
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Mignon
10 months ago
I'm not sure, but A sounds logical.
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Darci
10 months ago
I agree, A seems like the right choice.
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Lai
10 months ago
I think A is the correct answer.
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Veta
10 months ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
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Tran
10 months ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
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Phil
10 months ago
B) index=web | stats sum (bytes) BY page server
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Marti
10 months ago
A) index=web | stats sum (bytes) BY page BY server
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Margot
11 months ago
I'm going with C. The 'AND' keyword makes it clear that we want to group by both page and server.
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Elin
10 months ago
C) index=web | stats sum(bytes) BY page AND server
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Marjory
10 months ago
A) index=web | stats sum (bytes) BY page BY server
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Willard
11 months ago
I agree with Sonia, because we need to show the total bytes for each unique combination of page and server.
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Rosendo
11 months ago
Option B looks good to me. It has the same grouping as A, but in a more concise way.
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Malcolm
10 months ago
I believe option A is the right choice because it specifically groups by page and server.
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Lorrie
10 months ago
I agree with you, option B seems more concise and still groups by both page and server.
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Louvenia
11 months ago
I think option A is the correct one. It groups by both page and server.
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Sonia
11 months ago
I think the answer is A) index=web | stats sum (bytes) BY page BY server.
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Malcolm
11 months ago
I think option A is the correct one. It groups the data by both page and server, which is what the question is asking for.
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Juan
10 months ago
Option D doesn't look right, it's using values instead of BY.
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King
10 months ago
I'm not sure about option C, it seems a bit off.
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Janet
11 months ago
I think option B might work too, it groups by both page and server.
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Portia
11 months ago
I agree, option A is the correct one.
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