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Snowflake Exam DSA-C02 Topic 2 Question 28 Discussion

Actual exam question for Snowflake's DSA-C02 exam

Question #: 28
Topic #: 2

[All DSA-C02 Questions]

All Snowpark ML modeling and preprocessing classes are in the ________ namespace?

Asnowpark.ml.modeling

Bsnowflake.sklearn.modeling

Csnowflake.scikit.modeling

Dsnowflake.ml.modeling

Show Suggested Answer

Suggested Answer: D

All Snowpark ML modeling and preprocessing classes are in the snowflake.ml.modeling namespace. The Snowpark ML modules have the same name as the corresponding module from the sklearn namespace. For example, the Snowpark ML module corresponding to sklearn.calibration is snow-flake.ml.modeling.calibration.

The xgboost and lightgbm modules correspond to snowflake.ml.modeling.xgboost and snow-flake.ml.modeling.lightgbm, respectively.

Not all of the classes from scikit-learn are supported in Snowpark ML.

by Remedios at Sep 13, 2024, 02:58 AM

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Tran

11 months ago

I'm not sure, but I think it's D) snowflake.ml.modeling

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Malcolm

11 months ago

I agree with Nikita, A) snowpark.ml.modeling makes sense

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Nikita

11 months ago

I think it's A) snowpark.ml.modeling

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Vallie

11 months ago

I'm still waiting for Snowflake to come up with a namespace called 'snowlake.ml.modeling' just to keep us on our toes.

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Glen

9 months ago

No, I believe it's D) snowflake.ml.modeling.

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Cecilia

9 months ago

D) snowflake.ml.modeling

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Allene

9 months ago

I think it's A) snowpark.ml.modeling.

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Lucina

10 months ago

A) snowpark.ml.modeling

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Gerald

11 months ago

Hmm, this is a tough one. I'm going to go with A, but I really hope I don't get snow-blindness from all this Snowpark talk.

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Michal

11 months ago

B and C sound like they're trying to trick us. Snowflake doesn't use scikit-learn or sklearn, so those can't be right.

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Felix

11 months ago

I'm leaning towards D. Snowflake has its own ML capabilities, so the namespace would be snowflake.ml.modeling.

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Georgeanna

10 months ago

Let's go with D) snowflake.ml.modeling then.

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Nickolas

10 months ago

I agree with you, D) snowflake.ml.modeling makes sense.

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Jacquelyne

10 months ago

I'm not sure, but I believe it's D) snowflake.ml.modeling.

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Kimberely

11 months ago

I think it's A) snowpark.ml.modeling.

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Essie

11 months ago

I'm pretty sure it's A. Snowpark is Snowflake's own ML platform, so the namespace would be snowpark.ml.modeling.

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Teddy

11 months ago

Yes, you're correct. Snowpark ML modeling classes are in the snowpark.ml.modeling namespace.

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Micaela

11 months ago

I think you're right, it should be A) snowpark.ml.modeling.

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