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SAP Exam C_ABAPD_2309 Topic 5 Question 19 Discussion

Actual exam question for SAP's C_ABAPD_2309 exam
Question #: 19
Topic #: 5
[All C_ABAPD_2309 Questions]

Class super has subclass sub. Which rules are valid for the sub constructor? Note: There are 2 correct answers to this question.

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Suggested Answer: B, C

The expression itab1 = corresponding #( itab2 ) is a constructor expression with the component operator CORRESPONDING that assigns the contents of the internal table itab2 to the internal table itab1. The following statements are true for using this expression:

B: itab1 and itab2 must have at least one field name in common. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables.If itab1 and itab2 do not have any field name in common, the expression will not assign any value to itab1 and it will remain initial or unchanged1

C: Fields with the same name and the same type will be copied from itab2 to itab1. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables.If the columns have the same name but different types, the assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1

The following statements are false for using this expression:

A: Fields with the same name but with different types may be copied from itab2 to itab1. This is not true, as explained in statement C.The assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1

D: itab1 and itab2 must have the same data type. This is not true, as the component operator CORRESPONDING can assign the contents of an internal table of one type to another internal table of a different type, as long as they have at least one field name in common. The target type of the expression is determined by the left-hand side of the assignment, which is itab1 in this case.The expression will create an internal table of the same type as itab1 and assign it to itab11


by Teddy at Jun 19, 2024, 09:33 AM

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Leanna
3 months ago
I'm confident that C and D are the right answers. The subclass constructor has to play by the rules set by the superclass, no exceptions!
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Daron
3 months ago
Haha, changing the method signature? That's a bold move, Candidate A! I'll stick with the more sensible options C and D.
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Brock
2 months ago
Candidate A: Well, I guess we'll have to wait and see which answers are correct.
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Breana
2 months ago
Candidate B: I disagree, I believe C and D are the valid rules for the sub constructor.
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Felicitas
2 months ago
Candidate A: I think A and C are the correct rules for the sub constructor.
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Gayla
4 months ago
Hmm, I'm not sure about option B. Evaluating import parameters after calling the superclass constructor doesn't sound right to me. I'll go with C and D.
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Tammy
2 months ago
Definitely, calling the constructor of super before using any components of your own instance is a must.
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Haydee
2 months ago
Yeah, I think C and D make more sense in terms of the constructor rules.
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Fausto
3 months ago
I agree with you, I think option B is incorrect. Let's go with C and D.
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Kenny
4 months ago
I think options C and D are the correct answers. The constructor of the superclass must be called before using any components of the subclass instance, and events of the subclass instance cannot be raised before the registration of a handler in the superclass.
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Theodora
3 months ago
Yes, the constructor of the superclass must be called before using any components of the subclass instance.
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Hana
3 months ago
I agree, options C and D are the correct answers.
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Lizette
4 months ago
I believe option A is also valid because the method signature can be changed in the subclass constructor.
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Vincenza
4 months ago
I agree with Layla, option C makes sense logically.
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Layla
4 months ago
I think option C is correct because the constructor of super must be called first.
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