Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

SAP C_ABAPD_2309 Exam

Certification Provider: SAP
Exam Name: SAP Certified Associate - Back-End Developer - ABAP Cloud
Duration: 180 Minutes
Number of questions in our database: 81
Exam Version: Apr. 03, 2024
C_ABAPD_2309 Exam Official Topics:
  • Topic 1: Single Topic
Disscuss SAP C_ABAPD_2309 Topics, Questions or Ask Anything Related

Currently there are no comments in this discussion, be the first to comment!

Free SAP C_ABAPD_2309 Exam Actual Questions

The questions for C_ABAPD_2309 were last updated On Apr. 03, 2024

Question #1

You have two internal tables itab1 and itab2.What is true for using the expression itab1 = corresponding #( itab2 )? Note: There are 2 correct answers to this question.

Reveal Solution Hide Solution
Correct Answer: B, C

The expression itab1 = corresponding #( itab2 ) is a constructor expression with the component operator CORRESPONDING that assigns the contents of the internal table itab2 to the internal table itab1. The following statements are true for using this expression:

B: itab1 and itab2 must have at least one field name in common. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables.If itab1 and itab2 do not have any field name in common, the expression will not assign any value to itab1 and it will remain initial or unchanged1

C: Fields with the same name and the same type will be copied from itab2 to itab1. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables.If the columns have the same name but different types, the assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1

The following statements are false for using this expression:

A: Fields with the same name but with different types may be copied from itab2 to itab1. This is not true, as explained in statement C.The assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1

D: itab1 and itab2 must have the same data type. This is not true, as the component operator CORRESPONDING can assign the contents of an internal table of one type to another internal table of a different type, as long as they have at least one field name in common. The target type of the expression is determined by the left-hand side of the assignment, which is itab1 in this case.The expression will create an internal table of the same type as itab1 and assign it to itab11


Question #2

Given the following Core Data Service View Entity Data Definition:

1 @AccessControl.authorizationCheck: #NOT_REQUIRED

2 DEFINE VIEW ENTITY demo_flight_info_join

3 AS SELECT

4 FROM scarr AS a

5 LEFT OUTER JOIN scounter AS c

6 LEFT OUTER JOIN sairport AS p

7 ON p.id = c.airport

8 ON a.carrid = c.carrid

9 {

10 a.carrid AS carrier_id,

11 p.id AS airport_id,

12 c.countnum AS counter_number

13 }

In what order will the join statements be executed?

Reveal Solution Hide Solution
Correct Answer: A

The order in which the join statements will be executed is:

scarr will be joined with scounter first and the result will be joined with sairport.

This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.

Therefore, the join statements will be executed as follows:

First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.

Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.


Question #3

Exhibit:

With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts? Note:

There are 2 correct answers to this question

Reveal Solution Hide Solution
Correct Answer: A, D

The following are the explanations for each statement:

A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is not possible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super.Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12

B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception.However, the CAST operator will not work for go_subl, as explained in statement A12

C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super.Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123

D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass-specific method of cl_subl, which is not inherited by cl_super.Therefore, the method call go_subl->subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123


Question #4

Which of the following are incomplete ABAP types? Note: There are 2 correct answers to this question.

Reveal Solution Hide Solution
Correct Answer: C, D

Incomplete ABAP types are types that do not specify all the attributes of a data type, such as the length, the number of decimal places, or the value range. Incomplete types can only be used for the typing of field symbols and formal parameters, not for the definition of data objects or constants.Incomplete types can be either predefined or user-defined1.

The following are incomplete ABAP types:

C) C is a type for character strings with a generic length. The length of the character string has to be specified when a data object or a constant is defined with this type.For example, DATA text TYPE c LENGTH 10 defines a data object named text with a type c and a length of 10 characters2.

D) P is a type for packed numbers with a generic length and a generic number of decimal places. The length and the number of decimal places of the packed number have to be specified when a data object or a constant is defined with this type.For example, DATA amount TYPE p LENGTH 8 DECIMALS 2 defines a data object named amount with a type p, a length of 8 bytes, and 2 decimal places3.

The following are not incomplete ABAP types, because they specify all the attributes of a data type:

A) String is a type for variable-length character strings. The length of the character string is determined at runtime and can vary from 0 to 2,147,483,647 characters. The length does not have to be specified when a data object or a constant is defined with this type.For example, DATA text TYPE string defines a data object named text with a type string and a variable length4.

B) T is a type for time values in the format HHMMSS. The length of the time value is fixed at 6 characters and does not have to be specified when a data object or a constant is defined with this type. For example, DATA time TYPE t defines a data object named time with a type t and a length of 6 characters.


Question #5

In a test method you call method cl_abap_unit_assert=>assert_equals( .. ) in the following way:

CLASS Itcl1 DEFINITION FOR TESTING RISK LEVEL HARMLESS DURATION SHORT.

PRIVATE SECTION.

METHODS m1 FOR TESTING.

ENDCLASS.

CLASS Itcl1 IMPLEMENTATION.

METHOD m1.

DATA: go_test_object TYPE REF TO zcl_to_be_tested.

CONSTANTS: Ico_exp TYPE string VALUE 'test2'.

CREATE OBJECT go_test_object.

cl_abap_unit_assert=>assert_equals(

EXPORTING

act = go_class->mv_attribute

exp = lco_exp

msg = 'assert equals failed ' && go_test_object->mv_attribute && ' ' && lco_exp

ENDMETHOD.

ENDCLASS.

What will happen if method parameters act and exp are not equal?

Reveal Solution Hide Solution
Correct Answer: D


Unlock all C_ABAPD_2309 Exam Questions with Advanced Practice Test Features:
  • Select Question Types you want
  • Set your Desired Pass Percentage
  • Allocate Time (Hours : Minutes)
  • Create Multiple Practice tests with Limited Questions
  • Customer Support
Get Full Access Now

Save Cancel