PRMIA Exam 8002 Topic 1 Question 80 Discussion

Actual exam question for PRMIA's 8002 exam

Question #: 80
Topic #: 1

[All 8002 Questions]

Let a, b and c be real numbers. Which of the following statements is true?

AThe commutativity of multiplication is defined by

BThe existence of negatives is defined by

CThe distributivity of multiplication is defined by

DThe associativity of multiplication is defined by

Show Suggested Answer

Suggested Answer: C

by Margot at May 24, 2024, 02:11 AM

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Elfriede

10 months ago

Haha, these statistics questions are always a bit tricky. I'm going to go with C and hope for the best!

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Oren

10 months ago

Wait, isn't the t-distribution used when the population variance is unknown? I'm going with D, the estimated mean divided by the estimated standard deviation has a Chi2-distribution.

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Giovanna

10 months ago

I'm pretty confident it's C. The standard deviation is the square root of the variance, so the estimated mean divided by the estimated standard deviation has a t-distribution.

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Carylon

9 months ago

So, the estimated mean divided by the estimated standard deviation follows a t-distribution.

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Belen

10 months ago

That makes sense, the standard deviation is the square root of the variance.

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Kate

10 months ago

I think you're right, the estimated mean divided by the estimated standard deviation has a t-distribution.

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Cordelia

10 months ago

I'm not sure, but B sounds right to me. The estimated mean divided by the estimated variance has a Chi2-distribution, right?

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Kimberely

9 months ago

C) The estimated mean divided by the estimated standard deviation has a t-distribution

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Deangelo

10 months ago

B) The estimated mean divided by the estimated variance has a Chi2-distribution

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Wenona

10 months ago

A) The estimated mean divided by the estimated variance has a t-distribution

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Whitney

11 months ago

Hmm, I think it's C. The estimated mean divided by the estimated standard deviation should follow a t-distribution for i.i.d. normally distributed observations.

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Ellsworth

10 months ago

Yes, that's correct. It follows a t-distribution.

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Karl

11 months ago

I agree, it should follow a t-distribution.

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