PRMIA Exam 8002 Topic 1 Question 80 Discussion

Actual exam question for PRMIA's 8002 exam

Question #: 80
Topic #: 1

[All 8002 Questions]

Let a, b and c be real numbers. Which of the following statements is true?

AThe commutativity of multiplication is defined by

BThe existence of negatives is defined by

CThe distributivity of multiplication is defined by

DThe associativity of multiplication is defined by

Show Suggested Answer

Suggested Answer: C

by Margot at May 24, 2024, 02:11 AM

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Elfriede

12 months ago

Haha, these statistics questions are always a bit tricky. I'm going to go with C and hope for the best!

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Oren

12 months ago

Wait, isn't the t-distribution used when the population variance is unknown? I'm going with D, the estimated mean divided by the estimated standard deviation has a Chi2-distribution.

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Giovanna

12 months ago

I'm pretty confident it's C. The standard deviation is the square root of the variance, so the estimated mean divided by the estimated standard deviation has a t-distribution.

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Carylon

11 months ago

So, the estimated mean divided by the estimated standard deviation follows a t-distribution.

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Belen

11 months ago

That makes sense, the standard deviation is the square root of the variance.

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Kate

11 months ago

I think you're right, the estimated mean divided by the estimated standard deviation has a t-distribution.

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Cordelia

12 months ago

I'm not sure, but B sounds right to me. The estimated mean divided by the estimated variance has a Chi2-distribution, right?

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Kimberely

11 months ago

C) The estimated mean divided by the estimated standard deviation has a t-distribution

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Deangelo

11 months ago

B) The estimated mean divided by the estimated variance has a Chi2-distribution

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Wenona

12 months ago

A) The estimated mean divided by the estimated variance has a t-distribution

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Whitney

1 years ago

Hmm, I think it's C. The estimated mean divided by the estimated standard deviation should follow a t-distribution for i.i.d. normally distributed observations.

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Ellsworth

1 years ago

Yes, that's correct. It follows a t-distribution.

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Karl

1 years ago

I agree, it should follow a t-distribution.

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