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NetApp Exam NS0-184 Topic 8 Question 40 Discussion

Actual exam question for NetApp's NS0-184 exam
Question #: 40
Topic #: 8
[All NS0-184 Questions]

You are using Broadcom BES-53248 switches for a cluster interconnect in a base configuration.

In this scenario, what is the minimum number of ISLs supported between the switches?

Show Suggested Answer Hide Answer
Suggested Answer: D

Contribute your Thoughts:

Ernie
1 months ago
Wait, did they just say 'Broadcom BES-53248 switches'? I thought those were only used for deep-sea fishing expeditions!
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Henriette
6 days ago
A) 1
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Lina
1 months ago
C) 3
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Carry
1 months ago
B) 2
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Antione
1 months ago
A) 1
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Corrinne
2 months ago
I got this! The answer is B - 2 ISLs. That's the minimum required for a redundant cluster interconnect. Easy peasy!
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Avery
2 months ago
Oh man, I'm totally stumped on this one. Maybe I should've paid more attention in class... D - 4 ISLs, just to hedge my bets?
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Nicolette
2 months ago
That makes sense, having 3 ISLs would provide better resiliency in case of a link failure.
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Angelica
2 months ago
Definitely C - 3 ISLs. That's the standard for cluster interconnects, isn't it? Time to brush up on my switch config knowledge!
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Emilio
22 days ago
That's right, 3 ISLs is the standard for cluster interconnects with Broadcom BES-53248 switches.
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Paz
1 months ago
Yes, you're correct. The minimum number of ISLs supported between the switches is 3.
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Shasta
2 months ago
Hmm, this is a tricky one. I'm going to guess B - 2 ISLs. That just seems like the most logical choice for a base configuration.
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Eden
1 months ago
User 4: D - 4 ISLs is my guess. More connections for stability.
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Kirby
1 months ago
User 3: I'll go with C - 3 ISLs. It might provide better redundancy.
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Kirk
2 months ago
User 2: I'm going with B - 2 ISLs. That seems like a good choice.
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Colby
2 months ago
User 1: I think the answer is A - 1 ISL.
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Mari
2 months ago
I disagree, I believe it's 3 because we need redundancy in the cluster interconnect.
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Nicolette
2 months ago
I think the minimum number of ISLs supported is 2.
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