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Huawei H12-891_V1.0 Exam - Topic 5 Question 58 Discussion

In the laboratory network, the network is built according to the following topology diagram, SWI is the default configuration, and SW2 disables the switch STP function.
D) No interface is backed up for blocking
A) SG0/0/2 for WI enters the Discarding state
B) SW2 and G0/0/1 enters the Discarding state
C) SW2 G0/0/2 enters discarding state
E) SWI's G0/0/1 enters the Discarding state

Huawei H12-891_V1.0 Exam - Topic 5 Question 58 Discussion

Actual exam question for Huawei's H12-891_V1.0 exam
Question #: 58
Topic #: 5
[All H12-891_V1.0 Questions]

In the laboratory network, the network is built according to the following topology diagram, SWI is the default configuration, and SW2 disables the switch STP function.

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Suggested Answer: D

by Timmy at Nov 14, 2024, 03:10 PM

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Laurel
10 months ago
G0/0/2 on SW2 should be in Discarding state for sure!
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Pearly
10 months ago
No way, I believe option D is correct.
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Lisbeth
10 months ago
Wait, how can SW2 disable STP and still have a Discarding state?
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Aron
11 months ago
I think SW2 will definitely enter Discarding too.
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Susana
11 months ago
SWI is the default, so G0/0/1 might go to Discarding.
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Markus
11 months ago
If SW2 has STP disabled, then I don't think any of its interfaces would enter a Discarding state, right? Maybe option D is the answer.
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Leonida
11 months ago
I’m a bit confused about the Discarding state. Does it mean that no traffic is passing through? I need to double-check my notes on that.
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Jennifer
11 months ago
I think I practiced a question similar to this where we had to determine which interfaces would enter a blocking state. I feel like it might be SWI's G0/0/1.
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Mattie
12 months ago
I remember something about STP states, but I'm not entirely sure how it applies here since SW2 has STP disabled.
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Ronald
12 months ago
I've got a strategy here. I'll start by identifying the potential loop points in the topology, then consider how STP would normally handle that, and finally think about how disabling STP on SW2 would change the expected port states.
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Deja
12 months ago
I'm a bit confused by the wording of the options. I'll need to re-read the question and the diagram carefully to make sure I understand the implications of the STP configuration.
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Coral
12 months ago
Ah, I think I see it now. Since STP is disabled on SW2, that means there won't be any port blocking to prevent loops. This could lead to one of the interfaces entering the Discarding state.
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Ciara
12 months ago
Okay, let me think this through step-by-step. With STP disabled on SW2, I'm guessing that's going to have some impact on the port states.
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Ashley
12 months ago
Hmm, this looks like a tricky one. I'll need to carefully analyze the topology diagram and the given information about the switch configurations.
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Audrie
2 years ago
I'm going with C. It's the only option that makes sense given the information provided. Though I'm still trying to figure out why someone would disable STP in the first place.
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Leota
2 years ago
Agreed. It's always important to consider the consequences of any network configuration changes.
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Diane
2 years ago
True, there must be a specific reason for disabling STP. It's important to understand the implications of doing so.
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Carman
2 years ago
Maybe they disabled STP for a specific reason. It's not common practice, but there could be a valid reason for it.
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Evelynn
2 years ago
I think C is the correct answer too. It seems like SW2 G0/0/2 would enter the Discarding state if STP is disabled.
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Lucille
2 years ago
Haha, this reminds me of that time I accidentally disabled STP on our production switch. Let's just say the network went down faster than a lead balloon.
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Deeanna
2 years ago
Lesson learned, always double check before making changes.
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Wilson
2 years ago
Did you manage to quickly fix the issue?
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Alex
2 years ago
I can only imagine the chaos that ensued.
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Miss
2 years ago
Oh no, that must have been a nightmare!
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Johanna
2 years ago
I believe the correct answer is E) SWI's G0/0/1 enters the Discarding state.
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Lisbeth
2 years ago
I agree with Lai, because SW2 disables the switch STP function.
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Lai
2 years ago
I think the answer is A) SG0/0/2 for WI enters the Discarding state.
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Felicitas
2 years ago
I think the question is trying to trick us. The way the topology is described, it seems like SWI would be the one entering the discarding state, not SW2.
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Sage
2 years ago
I'm not sure, let's review the diagram again.
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Azzie
2 years ago
But what about option A, SG0/0/2 for WI enters the Discarding state?
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Vinnie
2 years ago
I think option E is correct, SWI's G0/0/1 enters the Discarding state.
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Rasheeda
2 years ago
I agree, it does seem like a trick question.
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Ellen
2 years ago
The correct answer is C. SW2's G0/0/2 enters the discarding state when the switch STP function is disabled.
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Harrison
2 years ago
Oh, I see. Thanks for clarifying!
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Richelle
2 years ago
Actually, the correct answer is C) SW2 G0/0/2 enters discarding state
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Fausto
2 years ago
No, I believe it is B) SW2 and G0/0/1 enters the Discarding state
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Detra
2 years ago
I think the correct answer is A) SG0/0/2 for WI enters the Discarding state
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