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Huawei H12-891_V1.0 Exam - Topic 1 Question 54 Discussion

Actual exam question for Huawei's H12-891_V1.0 exam

Question #: 54
Topic #: 1

[All H12-891_V1.0 Questions]

What is the correct description of the scene shown in the following figure?

AR1 simultaneously exists level-1 and Level-2 LSDB

BR1 can ping the interface address of R2 loopback 0

CR1 has a route to R2 loopback 010022/32

DThere is no neighbor relationship between R1 and R2

Show Suggested Answer

Suggested Answer: A, C

by Aide at Sep 19, 2024, 04:04 PM

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Craig

7 months ago

R1 existing in both LSDB levels? Sounds unlikely to me.

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Ceola

7 months ago

I'm surprised there's no neighbor relationship, that seems odd.

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Anglea

7 months ago

Wait, how can R1 have routes if there's no neighbor relationship?

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Orville

7 months ago

I agree, option B is definitely correct!

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Marti

7 months ago

R1 can ping R2's loopback, that's a fact.

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Queen

8 months ago

I'm leaning towards D because I think neighbor relationships are crucial, but I can't remember how to confirm if they exist or not.

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Naomi

8 months ago

I feel like I saw something about route entries in a similar question, so maybe C is the right choice, but I need to double-check my notes.

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Catalina

8 months ago

I remember a practice question about pinging loopback addresses, so option B sounds familiar, but I can't recall the specifics.

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Iesha

8 months ago

I think option A might be correct, but I'm not entirely sure how to determine if R1 exists in both LSDBs.

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Denae

8 months ago

This is a tricky question, but I'm going to take my time and think it through step-by-step. I don't want to rush and make a mistake.

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Quentin

8 months ago

I'm feeling pretty confident about this one. The options seem clear, and I believe I can identify the correct description based on the information given.

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Ammie

8 months ago

Okay, I think I've got this. The key is to focus on the specific details provided in the question and match them to the answer choices.

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Denae

8 months ago

Hmm, I'm a bit confused by the wording of the options. I'll need to carefully read through each one to determine the correct description.

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Hortencia

8 months ago

This question seems straightforward, but I want to make sure I understand the details before selecting an answer.

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Brice

9 months ago

This is a tricky one. I'll need to draw on my knowledge of temperature measurement principles to come up with the right answer.

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Jacquline

2 years ago

Option A? Really? I thought this was a networking exam, not a shape-shifting quiz!

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Jeniffer

2 years ago

This question is a bit tricky. I'd go with C, but I'm not 100% sure.

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Zoila

2 years ago

I'm not sure about that, I would go with A) R1 simultaneously exists level-1 and Level-2 LSDB.

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Maile

2 years ago

I agree with you, I also think it's B) R1 can ping the interface address of R2 loopback 0.

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Ceola

2 years ago

I think the correct answer is B) R1 can ping the interface address of R2 loopback 0.

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Bea

2 years ago

D seems more likely. If there's no neighbor relationship, then R1 wouldn't be able to see R2's loopback address.

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Selma

2 years ago

I think B is the right answer. If R1 can ping R2's loopback, then they must have a valid adjacency.

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Amie

2 years ago

C) R1 has a route to R2 loopback 010022/32

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Evangelina

2 years ago

B) R1 can ping the interface address of R2 loopback 0

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Claudia

2 years ago

A) R1 simultaneously exists level-1 and Level-2 LSDB

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Amie

2 years ago

I'm not sure, but I think it might be A) R1 simultaneously exists level-1 and Level-2 LSDB.

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Lashonda

2 years ago

I agree with Titus. R1 being able to ping R2's loopback 0 address makes sense.

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Arthur

2 years ago

Option C looks correct to me. R1 should have a route to the loopback interface of R2 if they're connected.

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Bette

2 years ago

Yeah, that's true. If they're connected, R1 should definitely have a route to R2's loopback interface.

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Christiane

2 years ago

I think option C is correct too. It makes sense that R1 would have a route to R2's loopback interface.

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Titus

2 years ago

I think the correct description is B) R1 can ping the interface address of R2 loopback 0.

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