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Huawei H12-351_V1.0 Exam - Topic 5 Question 40 Discussion

When calculating the number of APs, you can divide the total required bandwidth by the maximum bandwidth of a single AP.
B) False
A) True

Huawei H12-351_V1.0 Exam - Topic 5 Question 40 Discussion

Actual exam question for Huawei's H12-351_V1.0 exam
Question #: 40
Topic #: 5
[All H12-351_V1.0 Questions]

When calculating the number of APs, you can divide the total required bandwidth by the maximum bandwidth of a single AP.

Show Suggested Answer Hide Answer
Suggested Answer: B

When calculating the number of APs, you cannot simply divide the total required bandwidth by the maximum bandwidth of a single AP. You also need to consider other factors such as signal coverage area, user density, interference level, and application type.


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Jesus
10 months ago
True, but you also need to consider user density!
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Jesusita
10 months ago
I thought it was more complicated than that.
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Kris
10 months ago
Wait, is that really accurate for all scenarios?
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Bok
11 months ago
Totally agree, it's a straightforward method.
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Susana
11 months ago
That's how you calculate it!
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Felix
11 months ago
I believe it's true, but I can't recall if there are exceptions based on the environment or specific AP models.
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Lorrine
11 months ago
I’m a bit confused; I thought we also had to account for user density and interference when calculating the number of APs.
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Francine
11 months ago
I feel like I've seen similar questions, and they usually emphasize that the maximum bandwidth of a single AP is just one part of the equation.
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Coral
12 months ago
I think this is true because I remember calculating APs by dividing total bandwidth before, but I'm not entirely sure if there are other factors to consider.
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Ora
12 months ago
This is a straightforward calculation, but I want to double-check my work. Dividing the total by the max per AP sounds right, but I'll walk through it step-by-step to be sure.
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Renea
12 months ago
I'm a little confused on this one. Is there something else I need to consider besides just the bandwidth numbers? I want to make sure I'm not missing anything.
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Bettina
12 months ago
Okay, I've got this. Dividing the total bandwidth by the max per AP will give me the number of APs required. Simple as that.
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Rochell
12 months ago
Wait, is that really the right approach? I'm not sure if that's the full story here. I'll need to think this through a bit more carefully.
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Thea
12 months ago
Hmm, this seems straightforward. I think I can just divide the total bandwidth by the max bandwidth per AP to get the number of APs needed.
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Tammara
2 years ago
Ha, this question is a total joke. As if it's that easy to figure out the number of APs. I bet the answer is something crazy like 'it depends on your deployment scenario'.
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Annice
2 years ago
Hmm, I'm not sure. Dividing bandwidth by AP capacity sounds logical, but there's gotta be more to it. I better double-check my notes.
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Remedios
2 years ago
Hold up, that can't be right. Don't we need to factor in things like interference and coverage area? This question is trying to trick us.
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Golda
2 years ago
Yeah, I agree. It's not just about dividing the total required bandwidth by the maximum bandwidth of a single AP.
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Jose
2 years ago
I think you're right, we need to consider other factors like interference and coverage area.
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Chan
2 years ago
B) False
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Willard
2 years ago
A) True
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Rebbecca
2 years ago
B) False
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Lauran
2 years ago
A) True
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Pete
2 years ago
But if you divide the total required bandwidth by the maximum bandwidth of a single AP, you can determine the number of APs needed. So, I still think it's A) True.
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Dalene
2 years ago
I disagree, I believe the answer is B) False.
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Jesus
2 years ago
Yep, that's the way to do it. Divide and conquer, right? Simple math, no brainer.
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Natalie
2 years ago
B) False
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Jillian
2 years ago
Exactly, divide and conquer. It's simple math.
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Jina
2 years ago
Divide and conquer, just like you said.
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Viola
2 years ago
True
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Talia
2 years ago
Exactly, it's a simple calculation.
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Alton
2 years ago
A) True
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Kerry
2 years ago
A) True
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Pete
2 years ago
I think the answer is A) True.
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