I've got this! The hexadecimal value OxFEDCBA has 6 digits, and each digit represents 4 bits. So the total number of bits is 6 * 4 = 24 bits, which is 3 bytes. The answer is C.
Wait, I'm a bit confused. Isn't a byte 8 bits? So wouldn't this 6-digit hexadecimal value take up 6 * 8 = 48 bits, which is 6 bytes? I'm not sure about this.
Okay, let me see... a hexadecimal value is represented using 4 bits per digit, so this 6-digit value should take up 6 * 4 = 24 bits, which is 3 bytes. I think the answer is C.
Hmm, this looks like a straightforward question about hexadecimal representation. I'll need to think through the number of bytes required to store this value.
Wait, wait, wait. If I had a hexadecimal value that was 12 digits long, that would be 48 bits, which is 6 bytes. So, option D must be the correct answer here. Clearly, the others are just guessing.
Alright, let's do this! The 'Ox' prefix indicates a hexadecimal number, and each hex digit is 4 bits. With 6 digits, that's 24 bits, or 3 bytes. Easy peasy, option C is the winner!
Hmm, let me think. If OxFEDCBA is a hexadecimal value, and each hexadecimal digit represents 4 bits, then the total number of bits would be 24. Dividing by 8 to get the number of bytes, that's 3. Gotta be option C!
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