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GAQM Exam CLSSBB-001 Topic 10 Question 61 Discussion

Actual exam question for GAQM's CLSSBB-001 exam
Question #: 61
Topic #: 10
[All CLSSBB-001 Questions]

A Belt working in a supply chain environment has to make a decision to change suppliers of critical raw materials for a new product upgrade. The purchasing manager is depending on the Belt's effort requiring that the average cost of an internal critical raw material component be less than or equal to $3,600 in order to stay within budget. Using a sample of 42 first article components, a Mean of the new product upgrade price of $3,200 and a Standard Deviation of $180 was estimated. Based on the data provided, the Z value for the data assuming a Normal Distribution is?

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Suggested Answer: D

Contribute your Thoughts:

Thurman
1 months ago
I hope the answer isn't 'Z' because that would be way too obvious. Let's go with 'Zorro' just for fun!
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Aleshia
22 hours ago
B) 4.67
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Nettie
14 days ago
A) 2.33
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Justine
1 months ago
Ugh, why do they always make these questions so convoluted? I need more coffee to tackle this one.
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Nydia
19 days ago
Yeah, I agree. Let's grab that coffee and work through this together.
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Arlette
21 days ago
I think the Z value for the data is 2.33.
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Phuong
24 days ago
I know right, these questions can be so confusing sometimes.
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Lucina
1 months ago
Piece of cake! This is right up my alley. I'm going to ace this question and impress the hiring manager.
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Cora
21 hours ago
A) 2.33
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Antonio
1 months ago
Wait, what's a Z-value again? I should have paid more attention in Statistics class.
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Kassandra
2 months ago
Hmm, this looks tricky. I better grab my calculator and start crunching some numbers.
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Louvenia
28 days ago
I think the Z value is 2.33.
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Wenona
1 months ago
A) 2.33
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Lyla
2 months ago
I agree. So, the closest option is A) 2.33. That seems like the correct answer.
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Veronique
2 months ago
Yes, that's correct. So, the Z value would be (3600 - 3200) / 180 = 2.22.
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Lyla
2 months ago
I think the Z value is calculated by subtracting the mean from the target value and dividing by the standard deviation.
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