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How many experimental runs exist in a Full Factorial and fully randomized design for 4 factors with 2 replicates for the Corner Points and no Center Points? The factors in the experiment are only at 2-levels.
Suggested Answer: C
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32 comments · newest first
CH
Chandra
11 months ago
Not sure about that, feels like it could be more.
LY
Lyndia
11 months ago
Totally agree, 32 is the right answer!
LA
Lacey
11 months ago
Wait, how do you get 64? That seems off.
JA
Jacquelyne
12 months ago
I think it’s 32 runs with 2 replicates.
NA
Nadine
12 months ago
There are 16 runs for 4 factors at 2 levels.
FE
Felicidad
12 months ago
I believe the answer is 64 because we have 2 replicates of the 16 runs from the full factorial design. I just hope I didn’t mix up the numbers!
RO
Rosamond
1 year ago
I’m a bit confused about the replicates part. If we only consider the corner points, does that change the total? I thought we still needed to account for all combinations.
TA
Tawna
1 year ago
I remember practicing a similar question, and I think the formula for the number of runs is something like levels^factors times replicates. So, that would be 16 times 2, which gives 32.
PA
Paola
1 year ago
I think for a full factorial design with 4 factors at 2 levels, the total runs should be 2^4, which is 16. But since we have 2 replicates, I’m not sure if that means we double it or not.
KI
Kizzy
1 year ago
Wait, didn't they say there were no center points? I need to double-check that detail.
VI
Vincent
1 year ago
I've got this! The number of runs is 2^4 = 16, and with 2 replicates that makes 32. Easy peasy.
VE
Verlene
1 year ago
Ugh, factorial designs always get me. I'll have to review my notes on calculating the total number of runs.
EV
Evette
1 year ago
Okay, let's see. Four factors, two levels each, and two replicates for the corner points. I think I can work this out.
MA
Margot
1 year ago
Hmm, this looks like a tricky one. I'll need to think through the factorial design and replication details carefully.
BU
Buck
1 year ago
Wait, so we're supposed to run 128 experiments just to test 4 factors? That's madness! I'm going to design my experiment with one factor at a time, that'll be way more efficient. *winks*
LE
Leatha
1 year ago
Ooh, this one's tricky! Let me think... Okay, I've got it! The answer is B) 128. Totally nailed it. *high fives self*
BR
Brandon
1 year ago
I'm going with C) 256. Wait, no, that can't be right... Ugh, I always get these factorial design questions mixed up! *grumbles*
RO
Rozella
1 year ago
D) 64
MI
Mirta
1 year ago
C) 256
AL
Alberta
1 year ago
B) 128
CA
Carmen
1 year ago
A) 10
ST
Stefany
1 year ago
Nah, I'm pretty sure it's D) 64. The question says there are no center points, so that means we only have the corner points with 2 replicates, right? Seems like the easiest answer to me.
BI
Billy
1 year ago
So, the answer is definitely D) 64. It's a straightforward calculation based on the information given.
MA
Mariann
1 year ago
Yeah, that's correct. With 4 factors at 2 levels and 2 replicates for corner points, it adds up to 64 runs.
AR
Arlette
1 year ago
I think you're right, D) 64 makes sense since there are no center points in the design.
VE
Verlene
1 year ago
Hmm, I think the answer is B) 128. That's the number of experimental runs for a full factorial design with 4 factors at 2 levels, right? Plus 2 replicates for the corner points.
GA
Gary
1 year ago
Great job! B) 128 is the correct answer.
JO
Joesph
1 year ago
That's right! It's 128 experimental runs for that design.
MA
Marlon
1 year ago
Yes, you are correct! The answer is B) 128.
KA
Karan
2 years ago
I'm not sure, but I think the answer might be C) 256. Can someone explain the rationale behind the correct answer?
EL
Elenora
2 years ago
I agree with Alisha, because for 4 factors at 2 levels with 2 replicates, the formula is 2^(number of factors) * number of replicates = 2^4 * 2 = 128.
AL
Alisha
2 years ago
I think the answer is B) 128.