GAQM CLSSBB-001 Exam - Topic 1 Question 66 Discussion

Actual exam question for GAQM's CLSSBB-001 exam

Question #: 66
Topic #: 1

How many experimental runs exist in a Full Factorial and fully randomized design for 4 factors with 2 replicates for the Corner Points and no Center Points? The factors in the experiment are only at 2-levels.

A10

B32

C256

D64

Show Suggested Answer

Suggested Answer: C

by Tasia at Feb 09, 2025, 03:11 PM

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Chandra

4 months ago

Not sure about that, feels like it could be more.

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Lyndia

5 months ago

Totally agree, 32 is the right answer!

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Lacey

5 months ago

Wait, how do you get 64? That seems off.

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Jacquelyne

5 months ago

I think it’s 32 runs with 2 replicates.

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Nadine

5 months ago

There are 16 runs for 4 factors at 2 levels.

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Felicidad

5 months ago

I believe the answer is 64 because we have 2 replicates of the 16 runs from the full factorial design. I just hope I didn’t mix up the numbers!

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Rosamond

6 months ago

I’m a bit confused about the replicates part. If we only consider the corner points, does that change the total? I thought we still needed to account for all combinations.

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Tawna

6 months ago

I remember practicing a similar question, and I think the formula for the number of runs is something like levels^factors times replicates. So, that would be 16 times 2, which gives 32.

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Paola

6 months ago

I think for a full factorial design with 4 factors at 2 levels, the total runs should be 2^4, which is 16. But since we have 2 replicates, I’m not sure if that means we double it or not.

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Kizzy

6 months ago

Wait, didn't they say there were no center points? I need to double-check that detail.

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Vincent

6 months ago

I've got this! The number of runs is 2^4 = 16, and with 2 replicates that makes 32. Easy peasy.

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Verlene

6 months ago

Ugh, factorial designs always get me. I'll have to review my notes on calculating the total number of runs.

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Evette

6 months ago

Okay, let's see. Four factors, two levels each, and two replicates for the corner points. I think I can work this out.

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Margot

6 months ago

Hmm, this looks like a tricky one. I'll need to think through the factorial design and replication details carefully.

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Buck

11 months ago

Wait, so we're supposed to run 128 experiments just to test 4 factors? That's madness! I'm going to design my experiment with one factor at a time, that'll be way more efficient. *winks*

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Leatha

11 months ago

Ooh, this one's tricky! Let me think... Okay, I've got it! The answer is B) 128. Totally nailed it. *high fives self*

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Brandon

11 months ago

I'm going with C) 256. Wait, no, that can't be right... Ugh, I always get these factorial design questions mixed up! *grumbles*

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Rozella

9 months ago

D) 64

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Mirta

9 months ago

C) 256

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Alberta

9 months ago

B) 128

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Carmen

9 months ago

A) 10

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Stefany

11 months ago

Nah, I'm pretty sure it's D) 64. The question says there are no center points, so that means we only have the corner points with 2 replicates, right? Seems like the easiest answer to me.

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Billy

10 months ago

So, the answer is definitely D) 64. It's a straightforward calculation based on the information given.

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Mariann

10 months ago

Yeah, that's correct. With 4 factors at 2 levels and 2 replicates for corner points, it adds up to 64 runs.

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Arlette

10 months ago

I think you're right, D) 64 makes sense since there are no center points in the design.

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Verlene

11 months ago

Hmm, I think the answer is B) 128. That's the number of experimental runs for a full factorial design with 4 factors at 2 levels, right? Plus 2 replicates for the corner points.

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Gary

11 months ago

Great job! B) 128 is the correct answer.

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Joesph

11 months ago

That's right! It's 128 experimental runs for that design.

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Marlon

11 months ago

Yes, you are correct! The answer is B) 128.

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Karan

1 year ago

I'm not sure, but I think the answer might be C) 256. Can someone explain the rationale behind the correct answer?

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Elenora

1 year ago

I agree with Alisha, because for 4 factors at 2 levels with 2 replicates, the formula is 2^(number of factors) * number of replicates = 2^4 * 2 = 128.

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Alisha

1 year ago

I think the answer is B) 128.

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