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EC-Council 212-81 Exam - Topic 2 Question 50 Discussion

Posted by Claudia on Jan 15, 2025 at 01:56 AM

A protocol for key aggreement based on Diffie-Hellman. Created in 1995. Incorporated into the public key standard IEEE P1363.

Suggested Answer: D

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30 comments · newest first
AR
Arleen 11 months ago
Nope, it's not Blum Blum Shub.
GA
Gail 11 months ago
I thought it was more recent than that!
MA
Malcom 11 months ago
Wait, is it really part of IEEE P1363? Sounds off.
IN
In 12 months ago
Agreed, it's a key agreement protocol from '95.
RO
Rocco 12 months ago
That's definitely about Menezes-Qu-Vanstone!
BI
Billye 1 year ago
I’m leaning towards Euler's totient, but I’m confused because it seems more related to RSA than Diffie-Hellman.
PA
Patti 1 year ago
I feel like I've seen a question about IEEE P1363 before, and it might have mentioned something about elliptic curves.
VI
Vincenza 1 year ago
I remember studying Diffie-Hellman, but I can't recall if it was specifically linked to any of these options.
AL
Alesia 1 year ago
I think the answer might be Menezes-Qu-Vanstone since it relates to key agreement, but I'm not entirely sure.
VI
Viva 1 year ago
Wait, I'm confused. Diffie-Hellman is a key agreement protocol, but the options don't seem to match that. I'll have to re-read the question and the choices more closely to figure this out.
BR
Brent 1 year ago
Okay, let's see. Diffie-Hellman is a key agreement protocol, and the question mentions it was created in 1995 and incorporated into a standard. I'm pretty confident I can identify the correct answer here.
LI
Linn 1 year ago
Hmm, I'm a bit unsure about this one. The details about the protocol and its incorporation into a standard are throwing me off. I'll have to think this through carefully.
RA
Raina 1 year ago
This question seems straightforward. I remember learning about Diffie-Hellman key agreement in class, so I think I can handle this one.
BR
Brandon 1 year ago
Blum Blum Shub? Really? That's like the name of a Harry Potter spell or something!
RO
Rosio 1 year ago
↳ replying to Brandon
D) Euler's totient
RA
Raelene 1 year ago
↳ replying to Brandon
C) Menezes-Qu-Vanstone
LA
Lanie 1 year ago
↳ replying to Brandon
B) Elliptic Curve
ST
Stephaine 1 year ago
↳ replying to Brandon
A) Blum Blum Shub
LA
Lavonne 1 year ago
Hmm, Diffie-Hellman... that sounds like it could be C, but I'm not convinced. Gotta double-check my notes.
IN
Inocencia 1 year ago
↳ replying to Lavonne
C) Menezes-Qu-Vanstone
SH
Shonda 1 year ago
↳ replying to Lavonne
B) Elliptic Curve
RO
Rosendo 1 year ago
↳ replying to Lavonne
A) Blum Blum Shub
MA
Marci 1 year ago
You know, if this was a Dungeons & Dragons game, I bet the Menezes-Qu-Vanstone protocol would be a totally epic spell!
OL
Olive 1 year ago
↳ replying to Marci
C) Menezes-Qu-Vanstone
JO
Joseph 1 year ago
↳ replying to Marci
B) Elliptic Curve
SA
Santos 1 year ago
↳ replying to Marci
A) Blum Blum Shub
KI
King 1 year ago
Wait, didn't Euler's totient have something to do with that? I'm getting confused...
EM
Emmett 2 years ago
I'm not sure, but I think Menezes-Qu-Vanstone could also be a possible answer.
JO
Josphine 2 years ago
I agree with Lemuel, Elliptic Curve makes sense for key agreement.
LE
Lemuel 2 years ago
I think the answer is Elliptic Curve.
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