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Dell EMC D-PWF-OE-00 Exam - Topic 6 Question 11 Discussion

What is the minimum number of nodes required for creating a Fault Set in PowerFlex?
D) 6
A) 2
B) 3
C) 4

Dell EMC D-PWF-OE-00 Exam - Topic 6 Question 11 Discussion

Actual exam question for Dell EMC's D-PWF-OE-00 exam
Question #: 11
Topic #: 6
[All D-PWF-OE-00 Questions]

What is the minimum number of nodes required for creating a Fault Set in PowerFlex?

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Suggested Answer: D

6 Nodes: To utilize the Fault Set feature (which provides higher availability than standard SDS grouping, typically for rack awareness), PowerFlex requires a minimum configuration.

The Math:

A Protection Domain requires a minimum of 3 Fault Sets to support the 2-copy mirroring (Primary, Secondary, and a third location for rebuilding if a set fails).

Dell PowerFlex engineering requirements state that each Fault Set must contain at least 2 SDS nodes to ensure local redundancy and performance balance within the set.

$3 text{ Fault Sets} times 2 text{ Nodes} = 6 text{ Nodes}$ minimum.


Contribute your Thoughts:

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It's 3 nodes for a Fault Set!
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Harley
5 days ago
I recall reading that 6 nodes are required for optimal redundancy, but I don’t think that’s the minimum for a Fault Set.
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Britt
10 days ago
I’m pretty confident it’s 2 nodes, but I could be mixing it up with another concept from the study material.
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Arthur
15 days ago
I practiced a similar question, and I feel like the answer might be 4 nodes. It just seems like a safer number.
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Gaynell
2 months ago
I think I remember something about needing at least 3 nodes for a Fault Set, but I'm not entirely sure.
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