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CIW Exam 1D0-541 Topic 3 Question 108 Discussion

Actual exam question for CIW's 1D0-541 exam
Question #: 108
Topic #: 3
[All 1D0-541 Questions]

Consider the Stu_Act and Act_Fee tables shown in the exhibit. Which relational algebraic

operation would yield the Activity Relation table in the exhibit?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Janet at Mar 04, 2025, 03:55 PM

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Pearly
3 months ago
The natural join is the way to go. It's like a secret handshake between the tables, making sure they only share the relevant information. Very clever, this one!
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Raylene
1 months ago
User 3: Making sure they only share the relevant information.
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Margarita
1 months ago
User 2: Yeah, it's like a secret handshake between the tables.
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Margurite
1 months ago
User 1: I think the natural join is the best option.
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Trinidad
3 months ago
Ah, the natural join, of course! It's like the perfect dance between the two tables, where they come together seamlessly. I can almost hear the music playing in the background.
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Linsey
1 months ago
User 4: It's like music playing in the background.
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Avery
2 months ago
User 3: It's true, they come together seamlessly.
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Yan
2 months ago
User 2: Yes, the natural join is like a perfect dance between the tables.
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Pete
2 months ago
User 1: I think the answer is C) Natural join.
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Whitley
3 months ago
Hmm, I'm not sure. Maybe the Cartesian product would work, but that might give us more data than we need. I'll have to think this one through carefully.
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Vannessa
3 months ago
The natural join operation would be the correct answer here. It combines the related data from the Stu_Act and Act_Fee tables based on the common attributes.
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Isaiah
2 months ago
The natural join operation would be the correct answer here. It combines the related data from the Stu_Act and Act_Fee tables based on the common attributes.
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Hassie
2 months ago
D) Cartesian product
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Linette
2 months ago
C) Natural join
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Zachary
2 months ago
B) Intersection
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Vannessa
2 months ago
A) Union
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Gertude
3 months ago
I'm not sure, but I think D) Cartesian product could also work if we want all possible combinations of rows.
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Candra
3 months ago
I agree with Marion, because we need to combine the tables based on a common attribute.
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Marion
4 months ago
I think the answer is C) Natural join.
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