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CIMAPRA17-BA2-1 Exam - Topic 1 Question 81 Discussion

Posted by Rebeca on Sep 15, 2024 at 12:51 AM

Every month for the last three years, a company has recorded the number of new customers for that month. The data have been summarised and grouped as follows:

What is the arithmetic mean of the number of new customers per month?

Suggested Answer: D

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31 comments · newest first
HE
Heike 11 months ago
The data shows a steady increase over the months.
SH
Sharmaine 11 months ago
Totally agree, 6.50 feels right to me!
CH
Chaya 11 months ago
Wait, are we sure about those numbers? Seems off.
CH
Chauncey 12 months ago
I think the mean is around 6.38!
FR
Frederick 12 months ago
The total number of new customers is crucial for this calculation.
JE
Jettie 1 year ago
I think I might lean towards option C, but I’m not entirely confident. I hope I remember the steps correctly!
MA
Margarett 1 year ago
I’m a bit confused about how to handle the grouped data. Do I need to find the midpoint for each group before calculating the mean?
AL
Altha 1 year ago
This question feels similar to one we did in class about customer data. I think the mean is found by dividing the total by the number of months.
RA
Rashida 1 year ago
I remember we practiced calculating the mean, but I’m not sure if I should sum the frequencies first or just the midpoints.
MU
Murray 1 year ago
Wait, is the frequency the number of months in each range? Or is it the number of times that range occurred? I'm a bit confused about how to interpret this data.
LI
Lili 1 year ago
Okay, I think I've got this. I'll multiply the midpoint of each range by the frequency, add those up, and then divide by the total number of months.
LE
Lenna 1 year ago
Hmm, I'm not sure how to handle the grouped data. Do I need to find the midpoint of each range and then calculate the mean?
GO
Golda 1 year ago
This looks like a straightforward calculation of the arithmetic mean. I'll need to add up the number of new customers and divide by the total number of months.
TR
Tracie 2 years ago
D) 8.50 has to be the answer. I mean, come on, who doesn't love a good 8.50 new customers per month? That's the kind of growth any business would dream of!
JE
Jerry 2 years ago
↳ replying to Tracie
D) 8.50 is not the correct arithmetic mean of the number of new customers per month.
MA
Margo 2 years ago
↳ replying to Tracie
C) 6.38 is also close, but not the correct answer.
KR
Kristeen 2 years ago
↳ replying to Tracie
B) 6.50 is close, but not the correct answer.
IO
Iola 2 years ago
↳ replying to Tracie
A) 6.22 is actually the correct arithmetic mean of the number of new customers per month.
LO
Loren 2 years ago
This is a piece of cake! C) 6.38 is clearly the correct answer. Although, I do wonder if the CEO eats cake every month to celebrate the new customers... Mmm, cake.
LA
Lavonna 2 years ago
I'm not sure, but I think the arithmetic mean is calculated by adding all the numbers and dividing by the total count. So, I would go with B) 6.50.
JE
Jettie 2 years ago
B) 6.50 seems like the right answer to me. The data shows a range of values, so 6.50 is a reasonable estimate of the mean.
MI
Miss 2 years ago
↳ replying to Jettie
I think 6.50 is the best choice based on the range of values shown in the data.
BR
Brett 2 years ago
↳ replying to Jettie
Yeah, the data is spread out, so 6.50 makes sense as the average.
ST
Stanford 2 years ago
↳ replying to Jettie
I agree, 6.50 seems like a reasonable estimate for the mean.
LA
Lajuana 2 years ago
I believe it's C) 6.38 because it seems to be the most balanced option.
TR
Trinidad 2 years ago
I think the answer is B) 6.50.
CA
Carmen 2 years ago
The correct answer is C) 6.38. I calculated the total number of new customers (77) and divided by the number of months (12) to get the arithmetic mean.
BO
Bobbye 2 years ago
↳ replying to Carmen
Oh, I see. Thanks for clarifying!
LI
Lindsay 2 years ago
↳ replying to Carmen
Actually, the correct answer is C) 6.38
ME
Merri 2 years ago
↳ replying to Carmen
No, I believe it is B) 6.50
FR
Francis 2 years ago
↳ replying to Carmen
I think the answer is A) 6.22
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