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C++ Institute CPP Exam - Topic 4 Question 88 Discussion

What happens when you attempt to compile and run the following code?#include #include #include #include using namespace std;templatestruct Out {ostream & out;Out(ostream & o): out(o){}void operator() (const T & val ) { out
A) 0 0
B) 0 1
C) 1 0
D) 1 1

C++ Institute CPP Exam - Topic 4 Question 88 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 88
Topic #: 4
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

};

bool Compare(char a, char b) { return tolower(a) < tolower(b);}

int main() {

char s[]={"qwerty"};

char t1[]={"ert"};

char t2[]={"ERT"};

sort(s, s+6);

cout<

return 0;

}

Program outputs:

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Suggested Answer: E

by Claribel at Jul 04, 2024, 06:00 PM

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Vallie
8 months ago
Compare function is case insensitive, so it matters!
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Tien
9 months ago
Wait, are you sure about that? Sounds off.
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Galen
9 months ago
Definitely 0 1, t2 should match.
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Deane
9 months ago
I think the output is 1 1!
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Yuonne
9 months ago
The sort function will rearrange the characters in s.
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Reuben
10 months ago
I feel like `includes` should return 1 for both `t1` and `t2` since the comparison is case insensitive, but I could be mixing it up with another function.
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Lucy
10 months ago
If I remember correctly, after sorting `s`, it should contain the characters in alphabetical order. So, I guess `t1` might be included, but I'm not sure about `t2`.
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Glenna
10 months ago
I remember practicing with `includes` before, and I think it checks if all elements of the second range are in the first, but I can't recall if case sensitivity matters.
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Tammi
10 months ago
I think the `sort` function will rearrange the characters in `s`, but I'm not sure how `includes` works with the custom comparator.
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Sherita
10 months ago
Alright, I've got a good understanding of the code now. I'll work through the logic step-by-step and make sure I can explain what's happening in the output.
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Chan
10 months ago
This seems straightforward enough. The `includes` function checks if one range is a subset of another, and the `Compare` function is used to do a case-insensitive comparison. I think I can handle this.
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Kaitlyn
10 months ago
I'm a bit confused by the `Compare` function and how it's being used in the `includes` calls. I'll need to review how `tolower` and custom comparison functions work in C++.
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Denise
10 months ago
Okay, let's see. The code is sorting the `s` array and then checking if the `t1` and `t2` arrays are subsets of the sorted `s` array using the `includes` function. I think I have a strategy for this.
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Ressie
10 months ago
Hmm, this looks like a tricky one. I'll need to carefully read through the code and understand what the `includes` function is doing.
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Rocco
10 months ago
Hmm, I'm a bit unsure about this one. The objectives all seem related to privacy and data handling, so I'll have to think carefully to determine which one is not an actual objective.
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Marlon
11 months ago
Setting seeAllData to 'true' in the test class? That doesn't sound right to me. I'd be worried that could introduce other issues or mask the real problem.
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Evangelina
1 year ago
Wait, wait, wait... the 'includes' function is case-sensitive? I thought it was case-insensitive! I guess I need to re-read the C++ documentation more carefully. *facepalm*
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Magnolia
1 year ago
The output will be 1 0, because the 'includes' function is case-sensitive, and 't1' (ert) is present in the sorted string 's' (eqrty), but 't2' (ERT) is not, since the comparison is case-sensitive.
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Rebecka
1 year ago
D) 1 1
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Marge
1 year ago
C) 1 0
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Thaddeus
1 year ago
B) 0 1
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Altha
1 year ago
A) 0 0
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Lizbeth
1 year ago
Hmm, this looks like a tricky one. I'll have to double-check the 'includes' function and the 'Compare' function to be sure, but my guess is that the output will be 0 1.
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Gerald
1 year ago
I think the output will be 1 1, because the 'includes' function checks if all the elements in the second range are present in the first range, and both 't1' (ert) and 't2' (ERT) are present in the sorted string 's' (eqrty).
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Goldie
1 year ago
Oh, I see. Thanks for the explanation.
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Goldie
1 year ago
No, the output will be 1 0 because 't1' (ert) is present in the sorted string 's' (eqrty) but 't2' (ERT) is not.
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Goldie
1 year ago
C) 1 0
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Jade
1 year ago
The output of the program will be 0 1, as the 'includes' function checks if all the elements in the second range are present in the first range, and the characters in 't2' (ERT) are all present in the sorted string 's' (eqrty), but the characters in 't1' (ert) are not all present in 's'.
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Martina
1 year ago
Characters in 't2' (ERT) are all present in the sorted string 's' (eqrty), but characters in 't1' (ert) are not all present in 's'.
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Martina
1 year ago
The 'includes' function checks if all elements in the second range are present in the first range.
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Martina
1 year ago
B) 0 1
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Rickie
1 year ago
Why do you think it's C) 1 0?
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Skye
1 year ago
I disagree, I believe the correct answer is C) 1 0.
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Rickie
1 year ago
I think the answer is B) 0 1.
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