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C++ Institute CPP Exam - Topic 1 Question 103 Discussion

What happens when you attempt to compile and run the following code?#include #include #include using namespace std;int main() {int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };map m;for(int i=0; i < 10; i++) {m[i]=t[i];}map::iterator it = find(m.begin(), m.end(), 5);cout
B) 4
A) 5
C) 10
D) compilation error

C++ Institute CPP Exam - Topic 1 Question 103 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 103
Topic #: 1
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

map m;

for(int i=0; i < 10; i++) {

m[i]=t[i];

}

map::iterator it = find(m.begin(), m.end(), 5);

cout<first;

return 0;

}

Program outputs:

Show Suggested Answer Hide Answer
Suggested Answer: B

by Doug at Jan 22, 2025, 04:52 PM

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Caprice
8 months ago
The iterator won't even be valid, so yeah, error all the way.
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Malinda
8 months ago
It's definitely not going to output 10, that's for sure!
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Sharee
8 months ago
Wait, is it really a compilation error? I thought it might output something.
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Jacquelyne
8 months ago
Totally agree, the find function won't work on a map like that.
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Phil
9 months ago
Looks like a compilation error to me.
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Noah
9 months ago
I’m leaning towards option D, a compilation error, because I don’t think `it?>first;` is valid syntax.
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Ben
9 months ago
I feel like the output should be the value associated with the key, but I’m confused about the syntax used in `cout`.
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Franklyn
9 months ago
I remember practicing a similar question where we had to find elements in a map, but I’m not sure if `find` works directly on maps like that.
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Lelia
9 months ago
I think the code will actually cause a compilation error because of the way the iterator is being used with `find`.
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Tesha
9 months ago
Aha, I think I've got it! The issue is that the find() function is looking for the value 5, but the map is storing the values from the array as the values, not the keys. So the iterator it will point to the key-value pair where the value is 5, not the key.
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Jesusita
9 months ago
Wait, I'm a bit confused. Doesn't the map store key-value pairs, not just values? How does the find() function know which key to return if it's just looking for a value?
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Latanya
9 months ago
No problem, I've got this. The find() function is looking for the value 5, so it should return an iterator pointing to the key-value pair with a value of 5. I'll just need to access the first element of that pair to get the key.
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Marti
9 months ago
Okay, I think I see the issue. The find() function is looking for a value in the map, not a key. I'll need to figure out how to properly access the key associated with the value we're searching for.
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Anissa
9 months ago
Hmm, this looks like a tricky one. I'll need to carefully step through the code and think about how the find() function works with a map.
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Dulce
1 year ago
I bet the output will be a rude message to the person who wrote this question. Seriously, who comes up with these tricky questions?
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Franchesca
1 year ago
Let's try running it and see if it actually gives a compilation error.
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Launa
1 year ago
Yeah, it's definitely a compilation error.
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Honey
1 year ago
I agree, this code looks like it will give a compilation error.
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Hayley
1 year ago
I think the output will be compilation error.
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Nobuko
1 year ago
Wait, why are we using `find()` on a `map` when we should be using `m.find(5)`? Developers these days, I tell you.
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Jesusita
1 year ago
Yeah, that's a mistake in the code. It should be `m.find(5)` to search for the key 5 in the map.
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Nickie
1 year ago
I think the correct way is to use `m.find(5)` instead of `find(m.begin(), m.end(), 5)`.
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Rasheeda
1 year ago
You're right, using `find()` on a `map` is incorrect.
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Joesph
1 year ago
I think the output will be 10. The `map` container stores key-value pairs, and we're trying to find the value associated with the key 5, which should be 10.
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Georgeanna
1 year ago
The correct answer is 4.
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Cherry
1 year ago
Actually, it will be 10.
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France
1 year ago
No, it will be 4.
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Natalie
1 year ago
I think the output will be 10.
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France
1 year ago
The output will be 4. The `find()` function will return an iterator pointing to the element with a key of 5, and we're trying to access the `first` member of that iterator, which is the key, not the value.
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Leana
1 year ago
B) 4
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Karan
1 year ago
A) 5
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Launa
1 year ago
The code will result in a compilation error. The `find()` function in the `map` container is used to search for a key, not a value.
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Gearldine
1 year ago
The output will be a compilation error.
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Giovanna
1 year ago
So, what will be the output then?
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Elli
1 year ago
Oh, I see. The find() function is used to search for a key, not a value.
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Cherry
1 year ago
You will get a compilation error.
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Billy
1 year ago
I also think it's D) compilation error, because find() function requires a specific key to search for in a map.
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Stevie
1 year ago
I agree with Santos, because the find() function cannot be used with map containers.
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Santos
1 year ago
I think the answer is D) compilation error.
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