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C++ Institute CPA-21-02 Exam - Topic 3 Question 50 Discussion

What happens when you attempt to compile and run the following code?#include #include #include using namespace std;int main(void){string s;s = "Test";s.resize (s.size() ? 1);cout
D) It prints: Tes 3
A) It prints: Test 4
B) It prints: Test 3
C) Compilation error

C++ Institute CPA-21-02 Exam - Topic 3 Question 50 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam
Question #: 50
Topic #: 3
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(void)

{

string s;

s = "Test";

s.resize (s.size() ? 1);

cout<

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: D

by Graciela at Mar 08, 2026, 03:29 AM

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Carissa
22 days ago
Wait, how does it not throw an error?
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Timothy
27 days ago
Totally agree, the string gets resized!
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Glory
1 month ago
It prints: Tes 3
upvoted 0 times
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Richelle
1 month ago
Not sure about that, seems like it should keep more characters.
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Vonda
1 month ago
Definitely option D, resizing to 1 keeps the first character.
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Terrilyn
2 months ago
Wait, why does it print "Tes"? That's weird!
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Mable
2 months ago
I think it should be a compilation error.
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Annelle
2 months ago
It prints: Tes 3
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Charisse
2 months ago
I’m a bit confused about the condition in the resize function. Does it really change the string to just one character? I need to think this through.
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Xochitl
2 months ago
I practiced a similar question where resizing a string affected its content. I feel like it might print "Tes 3" because of that.
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Valentine
2 months ago
I remember something about the resize function. It might change the string size, but I can't recall if it keeps the original characters.
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Fletcher
3 months ago
I think the code should compile fine since it looks correct, but I'm not sure what the output will be.
upvoted 0 times
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