What happens when you attempt to compile and run the following code?#include #include #include using namespace std;int main(void){string s;s = "Test";s.resize (s.size() ? 1);cout

C++ Institute CPA-21-02 Exam - Topic 3 Question 50 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 50
Topic #: 3

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main(void)

{

string s;

s = "Test";

s.resize (s.size() ? 1);

cout<

return 0;

}

AIt prints: Test 4

BIt prints: Test 3

CCompilation error

DIt prints: Tes 3

Show Suggested Answer

Suggested Answer: D

by Graciela at Mar 08, 2026, 03:29 AM

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Terrilyn

3 days ago

Wait, why does it print "Tes"? That's weird!

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Mable

8 days ago

I think it should be a compilation error.

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Annelle

13 days ago

It prints: Tes 3

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Charisse

19 days ago

I’m a bit confused about the condition in the resize function. Does it really change the string to just one character? I need to think this through.

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Xochitl

24 days ago

I practiced a similar question where resizing a string affected its content. I feel like it might print "Tes 3" because of that.

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Valentine

29 days ago

I remember something about the resize function. It might change the string size, but I can't recall if it keeps the original characters.

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Fletcher

1 month ago

I think the code should compile fine since it looks correct, but I'm not sure what the output will be.

upvoted 0 times

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