C++ Institute CPA-21-02 Exam - Topic 2 Question 48 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 48
Topic #: 2

[All CPA-21-02 Questions]

What is the output of the program?

#include

using namespace std;

union t

{

char c;

int i;

};

class First

{

union t u;

public:

First() {

u.c = 'A';

}

void Print(){

cout << u.c;

}

};

int main()

{

First *t = new First();

t?>Print();

}

AGarbage value

BIt prints: A

CIt prints: A 65

DCompilation error

Show Suggested Answer

Suggested Answer: B

by Kris at Jan 05, 2026, 05:16 AM

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Arlen

2 months ago

I believe it will compile fine. No errors.

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Layla

2 months ago

But what about the pointer syntax? Is it correct?

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Lashawn

3 months ago

Yeah, the constructor sets u.c to 'A'.

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Maurine

3 months ago

I think it prints: A.

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Tasia

3 months ago

How can it print both A and 65? That seems off.

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Charlene

3 months ago

I think it might throw a compilation error.

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Becky

3 months ago

Wait, isn't there a chance of a garbage value?

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Tijuana

3 months ago

Definitely B, no doubt!

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Layla

4 months ago

It prints: A

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Dominga

4 months ago

Lol, the program will probably just print a random garbage value. You can't trust unions!

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Dion

4 months ago

Haha, I bet the compiler will throw a fit and give us a compilation error. D all the way!

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Albina

4 months ago

Definitely B. The union will initialize the 'c' member to 'A'.

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Kenneth

5 months ago

Hmm, I'm not sure about this one. Could be B or C.

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Kimberlie

5 months ago

I'm pretty sure the answer is B. It prints 'A'.

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Irma

5 months ago

The output should be 'A'.

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Laurel

5 months ago

I feel like there might be a compilation error due to the way the Print function is called with the arrow operator.

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Billi

6 months ago

I practiced a similar question, and I think it should print 'A' because the Print function directly accesses the character.

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Danica

6 months ago

I'm not sure, but I remember something about unions that might cause a garbage value if not handled properly.

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Cordie

6 months ago

I think the output should be 'A' since the constructor initializes the union with 'A'.

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Beatriz

6 months ago

I've got it! The union will store the 'A' character, but when we print it, it will print the ASCII value 65 instead of just the character. The answer is C.

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Tyra

6 months ago

I'm not sure about this one. The question mentions "output of the program", so it might be related to how the program is executed, not just the union.

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Paulene

6 months ago

Okay, let me think this through. The union has a char and an int member, and the First class initializes the char member to 'A'. So the output should be just 'A'.

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