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C++ Institute CPA-21-02 Exam - Topic 1 Question 52 Discussion

What happens when you attempt to compile and run the following code?#include using namespace std;class A {public:int x;A() { x=0;}};class B : public A {public:B() { x=1;}};class C : private B {public:C() { x=2;}};int main () {C c1;cout
D) Compilation error
A) It prints: 210
B) It prints: 110
C) It prints: 010

C++ Institute CPA-21-02 Exam - Topic 1 Question 52 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam
Question #: 52
Topic #: 1
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

class A {

public:

int x;

A() { x=0;}

};

class B : public A {

public:

B() { x=1;}

};

class C : private B {

public:

C() { x=2;}

};

int main () {

C c1;

cout << c1.x;

return 0;

}

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Suggested Answer: D

by Lino at Apr 09, 2026, 01:02 PM

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Delila
1 day ago
Definitely a compilation error!
upvoted 0 times
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Georgene
7 days ago
It prints: 010
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Elza
12 days ago
Totally agree with the compilation error theory!
upvoted 0 times
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Margery
17 days ago
Wait, why can't we access x from C?
upvoted 0 times
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Vallie
22 days ago
I think it prints 210.
upvoted 0 times
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Alishia
2 months ago
No way, it should be a compilation error!
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Lenora
2 months ago
It prints: 010
upvoted 0 times
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Rupert
3 months ago
I’m leaning towards a compilation error because of the private inheritance from B. I don’t think main can access x in class C.
upvoted 0 times
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Lou
3 months ago
I practiced a similar question where inheritance affected variable access. I think this one might print 0 or 1, but I can't recall exactly how private inheritance works here.
upvoted 0 times
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Adelaide
3 months ago
I remember something about private inheritance. I feel like that might prevent access to x in class C, which could lead to a compilation error.
upvoted 0 times
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Chaya
3 months ago
I think the code will compile, but I'm not sure what value will be printed. It seems like it should be 2 since C sets x to 2.
upvoted 0 times
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