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ASQ CQE Exam - Topic 2 Question 122 Discussion

Actual exam question for ASQ's CQE exam
Question #: 122
Topic #: 2
[All CQE Questions]

If the mean time between failures (MTBF) for a device is 200 hours, what is the constant failure rate per hour?

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Suggested Answer: B

The constant failure rate per hour is calculated as the inverse of the mean time between failures (MTBF). Given an MTBF of 200 hours: Failure rate () = 1 / MTBF = 1 / 200 = 0.005


by Tuyet at Mar 02, 2026, 06:12 AM

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Chuck
15 days ago
Wait, are we sure about that? Seems off to me.
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Daren
20 days ago
Totally agree, it's definitely 0.005!
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Aileen
25 days ago
The failure rate is the inverse of MTBF, so it's 0.005.
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Yolande
1 month ago
Just to clarify, that's 1 failure every 200 hours, right?
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Maryln
1 month ago
I thought it would be higher, but yeah, 0.005 makes sense.
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Ronna
1 month ago
Wait, are we sure about that? Seems off to me.
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Chantay
2 months ago
Totally agree, it's definitely 0.005!
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Brett
2 months ago
The failure rate is the inverse of MTBF, so it's 0.005.
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Lai
2 months ago
I recall that the failure rate is usually expressed per hour, so I think it’s definitely 0.005, but I’m a bit hesitant.
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Reynalda
2 months ago
I feel like I might be mixing up the options. Is 0.002 the right answer? That seems low for a failure rate.
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Yong
2 months ago
I remember practicing a similar question, but I’m not entirely sure if I should convert it to a percentage or just keep it as a decimal.
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Whitney
2 months ago
I think the failure rate is the inverse of MTBF, so it should be 1 divided by 200, which is 0.005, right?
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