ASQ CQE Exam - Topic 2 Question 122 Discussion

Actual exam question for ASQ's CQE exam

Question #: 122
Topic #: 2

[All CQE Questions]

If the mean time between failures (MTBF) for a device is 200 hours, what is the constant failure rate per hour?

A0.005

B0.002

C0.500

D0.200

Show Suggested Answer

Suggested Answer: B

The constant failure rate per hour is calculated as the inverse of the mean time between failures (MTBF). Given an MTBF of 200 hours: Failure rate () = 1 / MTBF = 1 / 200 = 0.005

by Tuyet at Mar 02, 2026, 06:12 AM

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Chantay

24 hours ago

Totally agree, it's definitely 0.005!

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Brett

6 days ago

The failure rate is the inverse of MTBF, so it's 0.005.

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Lai

11 days ago

I recall that the failure rate is usually expressed per hour, so I think it’s definitely 0.005, but I’m a bit hesitant.

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Reynalda

16 days ago

I feel like I might be mixing up the options. Is 0.002 the right answer? That seems low for a failure rate.

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Yong

22 days ago

I remember practicing a similar question, but I’m not entirely sure if I should convert it to a percentage or just keep it as a decimal.

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Whitney

27 days ago

I think the failure rate is the inverse of MTBF, so it should be 1 divided by 200, which is 0.005, right?

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