Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

ASQ Exam CQE Topic 10 Question 95 Discussion

Actual exam question for ASQ's CQE exam
Question #: 95
Topic #: 10
[All CQE Questions]

The number of runs required by a full-factorial design with three factors each at two levels is equal to

Show Suggested Answer Hide Answer
Suggested Answer: C

Contribute your Thoughts:

Carmela
14 days ago
Wait, isn't a full-factorial design the one where you test every possible combination? That sounds like a lot of work - I'll stick to my 2^k designs, thank you very much!
upvoted 0 times
...
Crissy
21 days ago
Trick question! The real answer is to order a pizza and take a break from studying. Factorial designs are the worst...
upvoted 0 times
...
Donte
22 days ago
D) 12 has got to be the right answer. I remember learning this in my statistics class. Glad I brushed up on my notes!
upvoted 0 times
...
Stephania
1 months ago
Hmm, I'm not so sure. I was always a bit shaky on factorial designs. Let me double-check the formula...
upvoted 0 times
C) 9
upvoted 0 times
...
Luke
2 days ago
A) 6
upvoted 0 times
...
Meghann
13 days ago
B) 8
upvoted 0 times
...
Diane
21 days ago
A) 6
upvoted 0 times
...
...
Tony
1 months ago
I think the answer is B. 8 runs are required for a full-factorial design with three factors at two levels. It's basic experimental design stuff!
upvoted 0 times
...
Freida
2 months ago
I'm not sure, but I think the answer might be D) 12 because each factor at two levels means 2^3 = 8 runs, and then we need to include all possible combinations, which would be 8 + 4 = 12.
upvoted 0 times
...
Rosalind
2 months ago
I agree with Rochell, because each factor at two levels means 2^3 = 8 runs, but we also need to include the full factorial, so it's 8 + 1 = 9.
upvoted 0 times
...
Rochell
2 months ago
I think the answer is C) 9.
upvoted 0 times
...

Save Cancel