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Arista ACE-P-ALE1.04 Exam - Topic 4 Question 124 Discussion

In bash scripting, which of the following is NOT valid way of evaluating an arithmetic expression?
C) $[]
A) $(( ))
B) ${}
D) let

Arista ACE-P-ALE1.04 Exam - Topic 4 Question 124 Discussion

Actual exam question for Arista's ACE-P-ALE1.04 exam
Question #: 124
Topic #: 4
[All ACE-P-ALE1.04 Questions]

In bash scripting, which of the following is NOT valid way of evaluating an arithmetic expression?

Show Suggested Answer Hide Answer
Suggested Answer: C

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Pedro
5 days ago
So, B) is the best choice for the answer.
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King
10 days ago
Yeah, let is also valid for arithmetic.
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Inocencia
15 days ago
I feel like A) $(( )) is definitely valid.
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Lon
20 days ago
C) $[] seems off too.
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Elden
25 days ago
I agree, ${} is for variable expansion.
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King
1 month ago
I think B) ${} is not valid.
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Shenika
1 month ago
D) let is definitely valid, no doubt about it!
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Mozell
1 month ago
C) $[] is also outdated, but still valid in some contexts.
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Lawrence
2 months ago
Wait, are you sure about that? I thought all of them worked.
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Tori
2 months ago
Totally agree, B is the odd one out!
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Corrie
2 months ago
B) ${} is not valid for arithmetic.
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Marylin
2 months ago
Let’s not forget about $(( )) being the most common!
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Meaghan
2 months ago
I thought $[] was also invalid?
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Dominga
2 months ago
Wait, are you sure about that?
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Rory
4 months ago
Totally agree, B is the odd one out!
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Svetlana
4 months ago
B) ${} is not valid for arithmetic.
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Gayla
5 months ago
Let is definitely valid, but I’m leaning towards ${} being the one that doesn’t fit for arithmetic.
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Karina
5 months ago
I think $[] is also a way to evaluate expressions, but I can't recall if it's still used in modern scripts.
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Rose
5 months ago
I’m not sure about ${}, but I feel like it’s more for variable expansion than arithmetic.
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Rana
5 months ago
I remember practicing with arithmetic expressions, and I think $(( )) is definitely valid.
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